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Alisiya [41]
3 years ago
10

A major car dealership has several stores in a big city. The owner wants to determine if there is a difference in the proportion

of SUVs that are sold at stores A and B. The owner gathers the sales records for each store from the past year. A random sample of 55 receipts from store A shows that 30 of the sales were for SUVs. Another random sample of 60 receipts from store B shows that 42 of the sales were for SUVs. Assuming conditions for inference are met, what is the 99% confidence interval for the difference in proportions of sales that are SUVs
Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

confidence interval = ( -0.38 , 0.08 )

Step-by-step explanation:

Given data :

n1 = 55 , n2 = 60 ,

Let P1 ( proportion of SUV sales at store A ) = 30 / 55 = 0.55

P2 ( sample proportion of SUV sales at store B ) = 42/60 = 0.70

The Z-value at 99% confidence Interval = 2.58

<u>Determine the 99% confidence interval for difference in proportion</u>

applying the formula below

( P1 - P2 ) ± Z ( \sqrt{p1( 1-p1)/n1  +  p2(1-p2)/n2}

Input values above into equation

confidence interval = ( -0.38 , 0.08 )

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2 years ago
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prohojiy [21]
Okay so lets look at the equation given
a ^{2} + {b}^{2} = {c}^{2}
this is the Pythagorean theorem, this equation holds true to all right angle triangles.

for the "a" and "b" terms must be the two shortest lengths and "c" must be the longest length.
why? because "c" represents the hypotenuse in this theorem and the hypotenuse is by definition the longest side of a right triangle.

(side note: always draw a picture, it helps a lot if you doodle a bit to get an idea of what you are working with)

we are given three lengths : 3 , 4, and 5 (im ignoring the measurements for now)

we can look at it two ways with a picture and through algebra

try to draw a right triangle with the given info. you'll see there are only two cases were this is possible the picture above is one case where this is not possible

now we can look at this algebraically
a = 3 \\ b = 4 \\ c = 5
(but "a" and "b" can swap lengths)

now with the Pythagorean theorem we can see how this plays out
{a}^{2} + {b}^{2} = {c}^{2} \\ {3 }^{2} + {4}^{2} = {5 }^{2} \\ 9 + 16 = 25 \\ 25 = 25
and heres with "a" and "b" lengths swapped
{4}^{2} + {3}^{2} = {5}^{2} \\ 16 + 9 = 25 \\ 25 = 25
now here's a case when we let 5 , our longest length , become a leg and let one our shorter lengths take the place of "c"

a = 5 \\ b = 3 \\ c = 4 \\ {5}^{2} + {3}^{2} = {4}^{2} \\ 25 + 9 = 16 \\ 34 = 16 \:
obviously 34 does not equal 16

hope this helped you out

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Step-by-step explanation:


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