Question

H=vt+1/2gt^2 solving for G GIVING BRAINLISEST

Answer 1

Answer:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

Step-by-step explanation:

So we have the equation:

$h=vt+\frac{1}{2}gt^2$

And we want to solve for g.

First, isolate g. To do so, subtract vt from both sides:

$h-vt=\frac{1}{2}gt^2$

Multiply both sides by 2:

$2h-2vt=gt^2$

Now, divide both sides by t^2:

$g=\frac{2h-2vt}{t^2}$

Expand:

$g=\frac{2h}{t^2}-\frac{2vt}{t^2}$

Simplify the second term:

$g=\frac{2h}{t^2}-\frac{2v}{t}$

And we're done!

Answer 2

Answer:

g = $\frac{2(h - vt)}{t^2}$

Step-by-step explanation:

Given

h = vt + $\frac{1}{2}$ gt² ( subtract vt from both sides )

h - vt = $\frac{1}{2}$ gt² ( multiply both sides by 2 to clear the fraction )

2(h - vt) = gt² ( divide both sides by t² )

$\frac{2(h-vt)}{t^2}$ = g