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guajiro [1.7K]
3 years ago
14

H=vt+1/2gt^2 solving for G GIVING BRAINLISEST

Mathematics
2 answers:
ololo11 [35]3 years ago
8 0

Answer:

g=\frac{2h}{t^2}-\frac{2v}{t}

Step-by-step explanation:

So we have the equation:

h=vt+\frac{1}{2}gt^2

And we want to solve for g.

First, isolate g. To do so, subtract vt from both sides:

h-vt=\frac{1}{2}gt^2

Multiply both sides by 2:

2h-2vt=gt^2

Now, divide both sides by t^2:

g=\frac{2h-2vt}{t^2}

Expand:

g=\frac{2h}{t^2}-\frac{2vt}{t^2}

Simplify the second term:

g=\frac{2h}{t^2}-\frac{2v}{t}

And we're done!

Ne4ueva [31]3 years ago
6 0

Answer:

g = \frac{2(h - vt)}{t^2}

Step-by-step explanation:

Given

h = vt + \frac{1}{2} gt² ( subtract vt from both sides )

h - vt = \frac{1}{2} gt² ( multiply both sides by 2 to clear the fraction )

2(h - vt) = gt² ( divide both sides by t² )

\frac{2(h-vt)}{t^2} = g

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