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solmaris [256]
2 years ago
6

If (a+b)(a-b)=21,a+b=7 and a-b=3 what Is the value of a

Mathematics
1 answer:
topjm [15]2 years ago
8 0

9514 1404 393

Answer:

  5

Step-by-step explanation:

Add the latter two equations and you get ...

  (a +b) +(a -b) = (7) +(3)

  2a = 10 . . . . . . . . . . . . . . . simplify

  a = 5 . . . . . . . divide by 2

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Answer:

See attachment for rectangle

Step-by-step explanation:

Given

A = (-6,0)

B = (-4,0)

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Required

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AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

So, we have:

AB = \sqrt{(-6 - -4)^2 + (0- 0)^2}

AB = \sqrt{(-2)^2 + (0)^2}

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Next, calculate the width using:

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This implies that, the width of the rectangle is 6 units.

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Hence, the points of the rectangle are:

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<em>See attachment for rectangle</em>

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I belive that the answer is the first one!

Step-by-step explanation:

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