Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
105% <span>Just move the decimal to the right 2 places or multiply times 100, same thing</span>
Answer:
51 hours
Step-by-step explanation:
$15 x 40 = $600
$15 x 1.50 = $22.5
$22.5 x 11 = $247.5
$600 + $247.5 = $847.5
40 + 11 = 51 hours
Answer:
no Solution
Step-by-step explanation:
-12x-12y=4\\ 3x+3y=0
12x-12y=4
add 12y to both sides
12x-12y+12y=4+12y
divid both sides by -12
\frac{-12x}{-12}=\frac{4}{-12}+\frac{12y}{-12}
simplfy
x=-\frac{1+3y}{3}
\mathrm{Substitute\:}x=-\frac{1+3y}{3}
\begin{bmatrix}3\left(-\frac{1+3y}{3}\right)+3y=0\end{bmatrix}
\begin{bmatrix}-1=0\end{bmatrix}
1/8 the fraction?
two eighths = 2/8=1/4
