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Darya [45]
3 years ago
11

HELLPP 1. Write the number in scientific notation, 5678.345=

Mathematics
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

5.678345 x 10^3

Step-by-step explanation:

Because you have to have a single digit number than is more than zero but less than 10 and then the extra numbers go to the right so then it can be a single digit and then you have scooted those number to the right three times so you can get your single number therefore thats your answer

Can i be made brainliest

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If she completely guesses on all of the questions, what is the probability that she gets two of the four questions correct?
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Answer:

D) 0.211

Step-by-step explanation:

The probability of getting a correct answer is 1/4, so the probability of an incorrect answer is 3/4.

The probability of 2 correct and 2 incorrect is (1/4)(1/4)(3/4)(3/4) = 9/256.

There are C(4,2) = 4·3/(2·1) = 6 ways to have some combination of 2 correct and 2 incorrect out of 4 questions. So, the probability of that result is ...

... 6 · 9/256 = 27/128 =0.2109375 ≈ 0.211

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4 years ago
-50 = -3x +34<br> I need help solving for x?
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Answer:

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Step-by-step explanation:

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4 years ago
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Step-by-step explanation:

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3 years ago
"You are dating Moon rocks based on their proportions of uranium-238 (half-life of about 4.5 billion years) and its ultimate dec
Olenka [21]

Step-by-step explanation:

a.

Initial mass of the isotope = x

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Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

N_o = initial mass of isotope  = x

N = mass of the parent isotope left after the time, (t)  = 59% of x = 0.59x

t_{\frac{1}{2}} = half life of the isotope  = 4.5 billion years

\lambda = rate constant

Now put all the given values in this formula, we get

0.59x=x\times e^{-(\frac{0.693}{\text{4.5 billion years}})\times t}

t = 3.4 billion years

The age a rock is 3.4 billion years.

b.

Initial mass of the isotope = x

Time taken by the sample to decay its mass by 35%= t

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

N_o = initial mass of isotope  = x

N = mass of the parent isotope left after the time, (t)  = 65% of x = 0.65x

t_{\frac{1}{2}} = half life of the isotope  = 4.5 billion years

\lambda = rate constant

Now put all the given values in this formula, we get

0.65x=x\times e^{-(\frac{0.693}{\text{4.5 billion years}})\times t}

t = 2.8 billion years

The age a rock is 2.8 billion years.

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4 years ago
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