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Butoxors [25]
3 years ago
13

Suppose f(x)=x+2. Find the graph of f(1/3x)

Mathematics
1 answer:
8090 [49]3 years ago
6 0

Answer:

f(x)=x+2.

f(1/3x)=1/3 x+2=(x+6)/3or x/3+2

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Which expression represents exponential decay
Lelu [443]

Given:

The exponential equations in the options.

To find:

The equation which represents exponential decay.

Solution:

The general exponential equation is

y=ab^x

where, a is initial value and b is growth rate.

If b<1, then it is an equation of exponential decay.

If b>1, then it is an equation of exponential growth.

In option A, b=31>1, i.e., exponential growth.

In option B, b=3.1>1, i.e., exponential growth.

In option C, b=0.13<1, i.e., exponential decay.

In option D, b=1.03>1, i.e., exponential growth.

Only y=10(0.13)^x represents exponential decay.

Therefore, the correct option is C.

5 0
3 years ago
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kap26 [50]
2. y=2x+3 

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3. y=-7x 
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6 0
3 years ago
Read 2 more answers
(x+y)^2 (x2+2xy+y2) pleas show all work
lakkis [162]

Answer:

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

​4

​​ +4x

​3

​​ y+6x

​2

​​ y

​2

​​ +4xy

​3

​​ +y

​4

​​  

Step-by-step explanation:

1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)

​2

​​ =a

​2

​​ +2ab+b

​2

​​ .

({x}^{2}+2xy+{y}^{2})({x}^{2}+2xy+{y}^{2})(x

​2

​​ +2xy+y

​2

​​ )(x

​2

​​ +2xy+y

​2

​​ )

2 Expand by distributing sum groups.

{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )+2xy(x

​2

​​ +2xy+y

​2

​​ )+y

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )

3 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2xy(x

​2

​​ +2xy+y

​2

​​ )+y

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )

4 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}({x}^{2}+2xy+{y}^{2})x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2x

​3

​​ y+4x

​2

​​ y

​2

​​ +2xy

​3

​​ +y

​2

​​ (x

​2

​​ +2xy+y

​2

​​ )

5 Expand by distributing terms.

{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}{x}^{2}+2{y}^{3}x+{y}^{4}x

​4

​​ +2x

​3

​​ y+x

​2

​​ y

​2

​​ +2x

​3

​​ y+4x

​2

​​ y

​2

​​ +2xy

​3

​​ +y

​2

​​ x

​2

​​ +2y

​3

​​ x+y

​4

​​  

6 Collect like terms.

{x}^{4}+(2{x}^{3}y+2{x}^{3}y)+({x}^{2}{y}^{2}+4{x}^{2}{y}^{2}+{x}^{2}{y}^{2})+(2x{y}^{3}+2x{y}^{3})+{y}^{4}x

​4

​​ +(2x

​3

​​ y+2x

​3

​​ y)+(x

​2

​​ y

​2

​​ +4x

​2

​​ y

​2

​​ +x

​2

​​ y

​2

​​ )+(2xy

​3

​​ +2xy

​3

​​ )+y

​4

​​  

7 Simplify.

{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x

​4

​​ +4x

​3

​​ y+6x

​2

​​ y

​2

​​ +4xy

​3

​​ +y

​4

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7 0
3 years ago
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Ahat [919]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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