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2 years ago

At Norman's Newsstand, 5 magazines cost $20.00. How many magazines could you buy with $44.00?

Mathematics

2 answers:

kobusy [5.1K]2 years ago

8 0

Answer: 11 magazines

Step-by-step explanation:

1) 20/5 = $4 per magazine

2) 44/4 = 11 magazines

labwork [276]2 years ago

5 0

Answer:

10 magazines

Step-by-step explanation:

5 magazines cost $20.00

You have $44.00

If 5 magazines cost $20.00

Then 10 magazines would cost $40.00

Since the maximum amount of money you can spend is $44.00, you can only buy 10 magazines for $40.00 and be left with $4.00.

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Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds, and is

swat32

Answer:

1/3

Step-by-step explanation:

Range of data set: 12 - 6 = 6

Given that there is a uniform distribution:

P(6<x<7) = 1/6

P(7<x<8) = 1/6

P(8<x<9) = 1/6

P(9<x<10) = 1/6

P(10<x<11) = 1/6

P(11<x<12) = 1/6

where x is weight loss

Probability that weight loss is more than 10 pounds:

P(10<x<11) + P(11<x<12) = 1/6 + 1/6 = 1/3

3 0

3 years ago

Line k has a slope of 2/3. If line m is parallel to line k, then it has a slope of

puteri [66]

Answer:

Line M would also have a slope of 2/3.

Step-by-step explanation:

When two line are parallel that means that they will never intersect.

In order for two lines to avoid intersection they would have to be at the same slope.

Since lines K and line M are parallel to each other they have to have the same slope.

6 0

3 years ago

Please help thank you

matrenka [14]

Answer:

25.9 yd

Step-by-step explanation:

$a^{2}$ + ${b^{2} }$ = $c^{2}$

$(17)^{2}$ + ${b^{2} }$ = $(31)^{2}$

289 + ${b^{2} }$ = 961

Subtract 289 on both sides

${b^{2} }$ = 672

$\sqrt{b^{2} }$ = $\sqrt{672}$

nearest tenth

b = 25.9 yd

7 0

2 years ago

Read 2 more answers

Which linear function has the greatest initial value? Which has the greatest rate of change? Use the drop-down menus to show you

Nat2105 [25]

Answer:

Step-by-step explanation:

4 0

2 years ago

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0 What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$

6 0

2 years ago