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MArishka [77]
3 years ago
10

At Norman's Newsstand, 5 magazines cost $20.00. How many magazines could you buy with $44.00?

Mathematics
2 answers:
kobusy [5.1K]3 years ago
8 0

Answer: 11 magazines

Step-by-step explanation:

1)     20/5 = $4 per magazine

2)     44/4 = 11 magazines

labwork [276]3 years ago
5 0

Answer:

<u>10 magazines</u>

Step-by-step explanation:

5 magazines cost $20.00

You have $44.00

If 5 magazines cost <u>$20.00</u>

Then 10 magazines would cost <u>$40.00</u>

Since the maximum amount of money you can spend is $44.00, you can only buy 10 magazines for $40.00 and be left with $4.00.

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Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
What is the location of the sum 11+(-5) with respect to 11 on a number line?
stealth61 [152]
B is the correct answer because it is 11-5

Hope this helps :)
3 0
3 years ago
Read 2 more answers
Plzzz help i need A.S.A.P
Vladimir79 [104]
Hope this helps you. :)

3 0
3 years ago
Read 2 more answers
An experiment consists of rolling a number cube (dice). What is the probability of rolling a number GREATER THAN 4? Express your
MrMuchimi

Answer:

1/3

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur

Probability = Expected/Total outcome

Since the experiment requires rolling a dice

S = {1, 2, 3, 4, 5, 6}

Total outcome n(S) = 6

Number greater than 4 are;

Events E = {5,6}

Expected outcome n(E) = 2

Probability of rolling a number greater then 4 = 2/6

Probability of rolling a number greater then 4 = 1/3

8 0
3 years ago
5(2x+6)= -4( -5 - 2x)+3x <br> Solve for x
lisov135 [29]

Answer: x = -7/2

Step-by-step explanation:

10x+ 30 = 20 +8x+ 3

10x+ 30=23+8x

10x-8x = 23-30

2x=-7

( a helpful app to help with these type of problems is photomath)

8 0
3 years ago
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