Find the rate of change of h(x) =-x² + 4x+2 from x=3 to x=7

If 25 Y - 80 is equal to minus 50 then the value of Y is

Murrr4er [49]

Answer:

Answer:25y=-50+80

25y=30

y=30/25

y=6/5....this is ur answer

Step-by-step explanation:

Step-by-step explanation:

4 0

3 years ago

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The two rectangles shown have equal areas. Find the value of x

Tema [17]

Answer:

x=18

Step-by-step explanation:

We need to find the areas of the rectangles

1st rectangle

A= l*w

A = (2x+4)*9

= 18x+36

2nd rectangle

A = l*w

= 15*(3x-30)

= 45x-450

Since the area of the rectangles are equal, we set these two equations equal

18x+36 = 45x-450

Subtract 18x from each side

18x-18x+36 = 45x-18x-450

36 = 27x-450

Add 450 to each side

36+450 =27x

486 = 27x

Divide by 27 on each side

486/27 = 27x/27

18=x

7 0

3 years ago

The price of 10 citrons and 7 fragrant wood apples is 55 units. The price of 7 citrons and 10 fragrant wood apples is 64 units.

a_sh-v [17]

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Further explanation:

Let x be the price of one citron and

y be the price of one fragrant

Then according to given statement

10x+7y = 55 Eqn 1

7x+10y = 64 Eqn 2

Multiplying equation 1 by 7

$7(10x+7y) = 7(55)\\70x+49y=385$

This will be equation 3.

Multiplying equation 2 by 10

$10(7x+10y) = 10(64)\\70x+100y=640$

This will be equation 4.

Subtracting equation 3 from equation 4

$70x+100y - (70x+49y) = 640-385\\70x+100y-70y-49y = 255\\51y = 255\\\frac{51x}{51} = \frac{255}{51}\\x = 5\\Putting\ x=5\ in\ equation\ 1\\10(5)+7y = 55\\50+7y = 55\\7y = 55-50\\7y = 5\\\frac{7y}{7} =\frac{5}{7}$

So,

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Keywords: Linear Equations, Solving system of linear equations

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago

A genetic experiment involving peas yielded one sample of offspring consisting of 420 green peas and 174 yellow peas. Use a 0.01

slavikrds [6]

Answer:

a) $z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

b) For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

Step-by-step explanation:

Data given and notation

n=420+174=594 represent the random sample taken

X=174 represent the number of yellow peas

$\hat p=\frac{174}{594}=0.293$ estimated proportion of yellow peas

$p_o=0.23$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of yellow peas is 0.23:

Null hypothesis: $p=0.23$

Alternative hypothesis: $p \neq 0.23$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.293 -0.23}{\sqrt{\frac{0.23(1-0.23)}{594}}}=3.649$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>3.649)=0.00026$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

b) Critical value

For this case we need to find a critical value that accumulates $\alpha/2$ of the area on each tail, we know that $\alpha=0.01$ , so then $\alpha/2 =0.005$ , using the normal standard table or excel we see that:

$z_{crit}= \pm 2.58$

Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 1% of significance.

5 0

3 years ago

Answers are

Nadya [2.5K]

Answer:

yes yes spare

Step-by-step explanation:

7 0

3 years ago

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