I need help with my homework .... It is passed due I have to get it done. If not I will get a F on it ... Please help me with it
1 answer:
a) see attachment for graph
b) D: [0, 2.5] <em>time cannot be negative so the x-values start at 0</em>
R: [0, 100] <em>height cannot be negative so the y-values start at 0</em>
c) 84 ft <em>refer to the red coordinate on the graph</em>
d) 1.75 seconds <em>refer to the blue coordinate on the graph</em>
e) 2.5 seconds <em>refer to the green coordinate on the graph</em>
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When looking for coordinates at the various given values, remember that x is time and y is height.
- If you are given time, then look at the y-value for height
- If you are given height, then look at the x-value for the time.
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Answer:
Probability that detector B goes off is '0.615'
Step-by-step explanation:
Given that:
1) Probability that detector A goes off and detector B does not go off is 0.25.
2)Probability that detector A does not go off is 0.35.
3)Probability that detector A goes off is (1-0.35)=0.65
Assuming that
Probability that detector B goes off is 'p' Hence the probability that detector B does not goes off is (1-p)
Thus the probability that detector A goes off and detector B does not go off is product of the individual probabilities
Probability that detector B goes off is '0.615'