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alexandr402 [8]
3 years ago
9

Which set of numbers represents a Pythagorean triple?

Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer:

52 , 165 , 173 is Pythagorean triple.

Step-by-step explanation:

Pythagorean triple;

a² + b² = c²

Computation:

88² + 105² ≠ 139²

39² + 80² ≠ 119²

38² + 198² ≠ 202²

52² + 165² = 173²

So,

52 , 165 , 173 is Pythagorean triple.

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Answer: x(x+1)(x-1)

Step-by-step explanation:

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x²-1=(x+1)(x-1)

x²-x=x(x-1)

ans:x(x+1)(x-1)

Step-by-step explanation:

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Rounded to the nearest tenth, approximately how many ounces is 82.4 kilograms?
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A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

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In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

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Answer:

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Step-by-step explanation:

hope that will help you

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