The area of the larger ttaingle is 12 cm squared
Answer:
D. 1.3
Step-by-step explanation:
Perimeter (square) = 4*side
4 = 4*side
side = 1
We have triangle QVR. QV is a hypotenuse.
If we look at the triangle QTR, QT is a hypotenuse.
QV should be less than QT.
Let's find QT using Pythagorean theorem.
c² = a² + b²
QT² = QR² + RT² = 1² + 1² = 2
QT = √2 ≈ 1.4
QV < QT
QV < 1.4
We have 1.3 and 1 that are less than 1.4, but 1 is a length of a leg of the triangle, so 1 is impossible.
Answer D. 1.3
Answer:
The point is in the fourth qaudrant
and, the point is 1 unit below the x-axis
Step-by-step explanation:
hope this helped
Okay so you would use cos? = adjacent/hypotenuse so cos? = 31/57 so to find the angle you would do cos^-1(31/57) = ? so ? = 57.05 degrees. make sure your calculator is in degree mode
Set up the two events
A = first card is a 9
B = second card is a 9
The probability for event A is
P(A) = 4/52
because there are four "9" cards out of 52 total
If event A happens first, and B follows, then the probability is
P(B|A) = 3/51
because there are 3 nines left over out of 52-1 = 51 total left over
No replacement has been made
The notation P(B|A) means "probability of event B given that event A has happened"
Multiply the probabilities
P(A and B) = P(A)*P(B|A)
P(A and B) = (4/52)*(3/51)
P(A and B) = (4*3)/(52*51)
P(A and B) = 12/2652
P(A and B) = 1/221
P(A and B) = 0.00452488687782
Rounded to 4 decimal places, the approximate answer is 0.0045
The exact answer as a fraction is 1/221
