Trying to finsh fast so help please

Martin is painting the shed shown. The shed is shaped like a cube. He wants to paint the outside walls of the shed using paint t

laila [671]

Answer:

13

Step-by-step explanation:

7 0

3 years ago

Find the length and width of 4 different rectangles such that each rectangle has an area of 24 square units. Write the length an

Ksenya-84 [330]

Answer:

77

Step-by-step explanation:

because im smart btw no treats involved

5 0

4 years ago

An airline charges the following baggage fees: $25 for the first bag and $35 for the second. Suppose 54% of passengers have no c

Triss [41]

Answer:

(a) The average baggage-related revenue per passenger is $15.70.

(b) The standard deviation of baggage-related revenue is $19.95.

(c) The expected revenue for 120 passengers is $1,884.

Step-by-step explanation:

Let the random variable X represent the baggage-related revenue per passenger.

It is provided that the baggage fees is $25 for the first bag and $35 for the second.

The probability model is:

X : 0 25 60

P (X) : 0.54 0.34 0.12

(a)

Compute the average baggage-related revenue per passenger as follows:

$E(X)=\sum {X\times P (X)}$

$=(0\times 0.54)+(25\times 0.34)+(60\times 0.12)\\\\=0+8.50+7.20\\\\=15.70$

Thus, the average baggage-related revenue per passenger is $15.70.

(b)

Compute the standard deviation of baggage-related revenue as follows:

$E (X^{2})=\sum X^{2}\times P(X)}\\\\=(0^{2}\times 0.54)+(25^{2}\times 0.34)+(60^{2}\times 0.12)\\\\=0+212.50+432\\\\=644.5\\$

$SD(X)=\sqrt{E(X^{2})-(E(X))^{2}}$

$=\sqrt{644.5-(15.7)^{2}}\\\\=19.950188\\\\\approx 19.95$

Thus, the standard deviation of baggage-related revenue is $19.95.

(c)

Compute the expected revenue for 120 passengers as follows:

$E(R)=n\times E(X)$

$=120\times 15.7\\\\=1884$

Thus, the expected revenue for 120 passengers is $1,884.

8 0

4 years ago

Which number below has the largest value? 54.026 54.029 54.0229 54.0269

muminat

54.029 be because .029 is bigger than .026. .029 hundredths is bigger than 0229 or 0269 thousandths

4 0

4 years ago

Read 2 more answers

Maria, bill, and change sent a total of 71 text messages during the weekend. change sent 2 times as many messages as bill. maria

VLD [36.1K]

Alright, we're dealing with a few values here, so let's give them some labels to save us some trouble down the road. We'll call the number of messages sent by Maria m, the number sent by Bill b and the number sent by Change (is that a real name?) c. We don't know exactly what each number is, but let's take a look at what information they do give us.

Change sent 2 times as many messages as Bill, or, using our variable for Change and Bill:

$c=2b$

We're also given that Maria sent 7 messages more than Bill, which we can represent with:

$m=b+7$

Notice that m and c are both in terms of b. We can use this for our next step. We're given at the beginning that together, Maria, Bill, and Change sent 71 messages over the weekend. As an equation using all of our variables, this translates to:

$m+b+c=71$

Since m and c are both in terms of b, we can substitute those expressions in and solve for b:

$(b+7)+b+2b=71\\ b+7+b+2b=71\\ 7+4b=71\\ 4b=64\\ b=16$

Now that know that Bill sent 16 texts, we can find the numbers for Change and Maria:

$m=b+7=16+7=23\\
c=2b=2(16)=32$

So, Bill sent 16 texts, Maria sent 23, and Change sent 32.

4 0

3 years ago