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Taya2010 [7]
3 years ago
5

Determine whether the proportion is true or false 15/33 equals 22 / 46​

Mathematics
2 answers:
Juliette [100K]3 years ago
6 0

Answer:

False

Step-by-step explanation:

It could be solved using the proportion method i.e multiply 15 by 46 and 33 by 22. Since the answer is not equal, it's false.

Oksi-84 [34.3K]3 years ago
5 0

Answer: False

Step-by-step explanation:

Lets assume 15/33=22/46

15x46=22x33 (according to the cross multiply rule)

690=726

Here^^ clearly the answer is not equal thus, the answer is false, hope this was helpful :D

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The diagonal of a square is 8 cm.
VladimirAG [237]

the length of the side of this square is 4\sqrt{2} \:or \:5.65cm

Answer:

Solutions Given:

let diagonal of square be AC: 8 cm

let each side be a.

As diagonal bisect square.

let it forms right angled triangle ABC .

Where diagonal AC is hypotenuse and a is their opposite side and base.

By using Pythagoras law

hypotenuse ²=opposite side²+base side²

8²=a²+a²

64=2a²

a²=\frac{64}{2}

a²=32

doing square root on both side

\sqrt{a²}=\sqrt{32}

a=±\sqrt{2*2*2*2*2}

a=±2*2\sqrt{2}

Since side of square is always positive so

a=4\sqrt{2} or 5.65 cm

6 0
3 years ago
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If 3t-7=5t, then 6t=?
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7 0
3 years ago
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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
Help!!! ASAP<br> A PASS OR FAIL!! Help
marysya [2.9K]

Answer:

48/73

Step-by-step explanation:

cos S in ratio = ?

cos S = Adjacent/hypothenus

adjacent is the dimension of line aside the opposite (the line facing angle S, the hypotenus(longest line)

adjacent = 48

hypothenus = 73

cos S= 48/73

5 0
4 years ago
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