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Vaselesa [24]
3 years ago
14

For several weeks, a server records the number of desserts, d, ordered by diners at each table and the tip, t, in dollars, he re

ceives from that table. He finds that there is a positive linear association between t and d that is best modeled by the equation t = 1.4d + 9.1.
Mathematics
1 answer:
larisa86 [58]3 years ago
5 0
In this equation the 9.1 would represent the amount the tip would have been before the adjustment is made (1.4d) for the dessert.
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garik1379 [7]

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6 0
3 years ago
X multiplied by 11 is less than or equal to 22
Julli [10]

Answer:

It depends on the value of x.

Step-by-step explanation:

11x less than or equal to 22? It depends on the value of x.

6 0
3 years ago
An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
John Sells Hamburgers For $3 Each and cheeseburgers for $3.50 each. One afternoon, he sells a total of 24 burgers for $79. How M
Alexxx [7]
Let the hamburgers be x and cheese burgers be y.

x + y = 24
3x + 3.5 y = 79

x = 24 - y.

Substituting the value of x,

3( 24 - y) + 3.5 y = 79

 72- 3y + 3.5 y = 79
72 + 0.5 y = 79

0.5y = 79 - 72 = 7
1/2 y = 7

thus, y = 7 * 2 = 14

Substituting the value for x,

x + y = 24
x + 14 = 24
x = 24-14 = 10
Thus, x = 10.

Thus, she sold 10 hamburgers and 14 cheeseburgers 
4 0
3 years ago
8.02 x 10^-2 in standard form
k0ka [10]
8.02 x 10^-2 = 8.02 * 0.01 = 0.0802 <span>in standard form</span>
6 0
3 years ago
Read 2 more answers
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