If x represents the fractional increase in the number of mathletes, and if problem-solving speed is jointly proportional to their speed and their number, we want ...
(1 +25%)(1 +x) = (1 +60%)
1 +x = 1.60/1.25 = 1.28
x = 0.28 = 28%
The team size must increase by 28% to solve all of the problems on time.
Prob of just quarter is 3/14 for a dime is 4/14 and for a nickel its 7/14 then all you do is multiply them all together to get 306122449/<span>10000000000 that took me way to long</span>
Equation: If m is the total number of minutes it takes him to complete his homework, 30% of m is given by 0.3m. Since 30% was done in 12 minutes, we have 0.3m=12.
