<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
98 Cm should be the answer
N = N (1+0.20)^5
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Here, that'd be 10000(1.20)^5, or 24883 trees.
Answer:
3,-3
Step-by-step explanation:
g(3)= (3)³+6(3)²-9(3)-54
= 27+54-27-54
=81-81
= 0
g(-3) = (-3)³+6(-3)²-9(-3)-54
= -27+54+27-54
= 27-27
= 0
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Answer: There is a 90% chance that the true proportion of teenagers who drive their own car to school will lie in (0.5907, 0.9093).
Step-by-step explanation:
Interpretation of a% confidence interval : A person can be a% confident that the true population parameter lies in it.
Here, A 90% confidence interval to estimate the true proportion of teenagers who drive their own car to school is found to be (0.5907, 0.9093).
i.e. A person can be 90% confident that the true proportion of teenagers who drive their own car to school lies in (0.5907, 0.9093).
Hence, correct interpretation is : There is a 90% chance that the true proportion of teenagers who drive their own car to school will lie in (0.5907, 0.9093).
