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Lapatulllka [165]
3 years ago
12

Each year, roughly 10^6 computer programmers each make about $ 10^5.

Mathematics
1 answer:
Xelga [282]3 years ago
5 0

Answer:

100,000,000,000

Step-by-step explanation:

1 000 000 times 100 000 = 100,000,000,000

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How to find the least common denominator of 3 fractions?
Lina20 [59]

Answer:

  Find the LCD of the first two, then the LCD of that and the third one.

Step-by-step explanation:

You can do it by finding the LCD of two of the denominators, then the LCD of that and the third denominator.

Or, you can factor each of the denominators and find their LCM by multiplying the unique factors to their highest powers.

___

<u>Example:</u>

  1/21 + 1/35 + 1/45

The LCD of 1/21 and 1/35 is (21·35)/5 = 105. The LCD of 1/105 and 1/45 is ...

  (105·45)/15 = 315

__

Using factoring ...

  • 21 = 3·7
  • 35 = 5·7
  • 45 = 3²·5

LCD = 3²·5·7 = 315

3 0
3 years ago
Please help. How do you find cosine, sine, cosecant and secant with this triangle? ​
Veseljchak [2.6K]

Hi there! You have to remember these 6 basic Trigonometric Ratios which are:

  • sine (sin) = opposite/hypotenuse
  • cosine (cos) = adjacent/hypotenuse
  • tangent (tan) = opposite/adjacent
  • cosecant (cosec/csc) = hypotenuse/opposite
  • secant (sec) = hypotenuse/adjacent
  • cotangent (cot) = adjacent/opposite
  • cosecant is the reciprocal of sine
  • secant is the reciprocal of cosine
  • cotangent is the reciprocal of tangent

Back to the question. Assuming that the question asks you to find the cosine, sine, cosecant and secant of angle theta.

What we have now are:

  • Trigonometric Ratio
  • Adjacent = 12
  • Opposite = 10

Looks like we are missing the hypotenuse. Do you remember the Pythagorean Theorem? Recall it!

  • a²+b² = c²

Define that c-term is the hypotenuse. a-term and b-term can be defined as adjacent or opposite

Since we know the value of adjacent and opposite, we can use the formula to find the hypotenuse.

  • 10²+12² = c²
  • 100+144 = c²
  • 244 = c²

Thus, the hypotenuse is:

\large \boxed{c = 2 \sqrt{61} }

Now that we know all lengths of the triangle, we can find the ratio. Recall Trigonometric Ratio above! Therefore, the answers are:

  • cosine (cosθ) = adjacent/hypotenuse = 12/(2√61) = 6/√61 = <u>(6√61) / 61</u>
  • sine (sinθ) = opposite/hypotenuse = 10/(2√61) = 5/√61 = <u>(5√61) / 61</u>
  • cosecant (cscθ) is reciprocal of sine (sinθ). Hence, cscθ = (2√61/10) = <u>√61/5</u>
  • secant (secθ) is reciprocal of cosine (cosθ). Hence, secθ = (2√61)/12 = <u>√</u><u>61</u><u>/</u><u>6</u>

Questions can be asked through comment.

Furthermore, we can use Trigonometric Identity to find the hypotenuse instead of Pythagorean Theorem.

Hope this helps, and Happy Learning! :)

5 0
3 years ago
Solve 0.7(5x+15)=2.9-(x+3)
Anni [7]
0.7(5x+15)=2.9 -(x+3)
3.5x+10.5=2.9-x-3
3.5x+10.5= -0.1- x
4.5x= -10.6
x= -2.3555...

Check:
0.7(5(-2.3555...) +15) = 2.9 -(x+3)
2.2555... = 2.2555...
6 0
3 years ago
If each foot of water in a lake screens out 60% of the light above, what percent of the light passes through 5 feet of water?
BartSMP [9]
The amount of light passing through each foot the water in the lake = 100% - 60% = 40%
The percent of light passing through 5 feet of water = 0.4^5 = 0.01024 = 1.02%
8 0
3 years ago
Please I need help PLEASE​
frutty [35]

Answer:

15/2.5  18/h

Step-by-step explanation:

5 0
3 years ago
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