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makkiz [27]
3 years ago
13

Brian works in the lab and feels an empty cylindrical flask with 200 cubic centimeters of liquid. The flask has a radius of 3 cm

and a height of 12 cm. What percent of the volume of the flask is not filled with liquid?
Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

<h2>49.49%</h2>

Step-by-step explanation:

volume of liquid in the flask= 200 cm^3

radius of the flask = 3 cm

height of the  flask= 12 cm

volume of flask is given by =

putting values and solving we get =396 cm^3

therefore the volume unfilled= 396-200= 196cm^3

therefore % of volume unfilled= 196/396*100= 49.49%

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Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached b
Advocard [28]

The question is incomplete.

The complete question is

Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached by a real estate agent representing a client who would like to exchange a parcel of land in North Carolina for Kase’s Maryland property. Kase agrees to the exchange.

What is Kase’s realized gain or loss, recognized gain or loss, and basis in the North Carolina property in each of the following alternative scenarios? (Loss amounts should be indicated by a minus sign. Leave no answer blank. Enter zero if applicable.)

a. The transaction qualifies as a like-kind exchange and the fair market value of each property is $907,500.

b. The transaction qualifies as a like-kind exchange and the fair market value of each property is $199,000.

Answer:

A. Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

B. Realised loss ( 199000 - 217000) = 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

Step-by-step explanation:

A.

Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

Here , we find that Kase has realised gain of $ 690,500 but recognised gain of $ 0 . It is so because Kase did not receive any boot and the transaction is a like-kind exchange. Therefore, the adjusted basis in new property = $ 217,000 ( as no gain is recognised ).

B.

Realised loss ( 199000 - 217000 )= 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

7 0
3 years ago
I need part b do I divide by 6 or multiple by 6
Shalnov [3]

Answer:

You need to multiply by 6. Hint it say's it costs $6 per square meter that means times

Step-by-step explanation:

6 0
3 years ago
There are $1.95 worth of nickels and quarters in a piggy bank there are three more nickels than quarters how many of each are in
Gennadij [26K]

Answer:

6 quarters and 9 nickels

Step-by-step explanation:

6 quarters is equal to $1.50. 6 nickels is equal to $0.30. Those together equal $1.80, then add the three nickels bringing your total to $1.95.

3 0
3 years ago
Read 2 more answers
The curve
kherson [118]

Answer:

Point N(4, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Anything to the 0th power is 1
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \sqrt{x - 3}<u />

<u />\displaystyle y' = \frac{1}{2}<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                                   \displaystyle y = (x - 3)^{\frac{1}{2}}
  2. Chain Rule:                                                                                                        \displaystyle y' = \frac{d}{dx}[(x - 3)^{\frac{1}{2}}] \cdot \frac{d}{dx}[x - 3]
  3. Basic Power Rule:                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{\frac{1}{2} - 1} \cdot (1 \cdot x^{1 - 1} - 0)
  4. Simplify:                                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}} \cdot 1
  5. Multiply:                                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}}
  6. [Derivative] Rewrite [Exponential Rule - Rewrite]:                                          \displaystyle y' = \frac{1}{2(x - 3)^{\frac{1}{2}}}
  7. [Derivative] Rewrite [Exponential Rule - Root Rewrite]:                                 \displaystyle y' = \frac{1}{2\sqrt{x - 3}}

<u>Step 3: Solve</u>

<em>Find coordinates</em>

<em />

<em>x-coordinate</em>

  1. Substitute in <em>y'</em> [Derivative]:                                                                             \displaystyle \frac{1}{2} = \frac{1}{2\sqrt{x - 3}}
  2. [Multiplication Property of Equality] Multiply 2 on both sides:                      \displaystyle 1 = \frac{1}{\sqrt{x - 3}}
  3. [Multiplication Property of Equality] Multiply √(x - 3) on both sides:            \displaystyle \sqrt{x - 3} = 1
  4. [Equality Property] Square both sides:                                                           \displaystyle x - 3 = 1
  5. [Addition Property of Equality] Add 3 on both sides:                                    \displaystyle x = 4

<em>y-coordinate</em>

  1. Substitute in <em>x</em> [Function]:                                                                                \displaystyle y = \sqrt{4 - 3}
  2. [√Radical] Subtract:                                                                                          \displaystyle y = \sqrt{1}
  3. [√Radical] Evaluate:                                                                                         \displaystyle y = 1

∴ Coordinates of Point N is (4, 1).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

4 0
2 years ago
a fuel mixture consists of 3 parts oil and 11 parts gasoline. the oil costs $0.75 per liter, and the gasoline costs $1.60 per li
kupik [55]

Answer:

Total selling price= $663.82

Selling price per liter= $1.69

Step-by-step explanation:

Giving the following information:

Proportion of oil and gasoline:

Oil= 3/14= 0.21

Gasoline= 11/14= 0.79

The oil costs $0.75 per liter.

The gasoline costs $1.60 per liter.

<u>First, we need to calculate the number of liters of oil and gasoline required:</u>

<u></u>

Oil= 0.21*392= 82.32 liters

Gasoline= 0.79*392= 309.68

<u>Now, the total cost to produce 392 liters:</u>

Total cost= 82.32*0.75 + 309.68*1.6

Total cost= $577.23

<u>Finally, the total and unitary selling price:</u>

Total selling price= 577.23*1.15= $663.82

Selling price per liter= 663.82 / 392= $1.69

6 0
3 years ago
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