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ruslelena [56]
2 years ago
10

This is asking “identity whether each of the following is a linear function” please ignore the quality tho. The question numbers

i need help on is 4-6

Mathematics
1 answer:
Svetlanka [38]2 years ago
7 0

Answer:

4. Yes 5.No 6. No

Step-by-step explanation:

To be short,a linear equation has a coefficient of only 1 degree.

If the degree is over 1 it isn't a linear equation.

4 is the linear equation since it x value 7x has a degree of 1.

5 isn't becuase it's x value has a degree of 5

6 isn't becuase it degree is 4.

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A paper company needs to ship paper to a large printing business. The a paper will be
eimsori [14]

Given :

A paper company needs to ship paper to a large printing business.

The paper will be shipped in small boxes and large boxes.

Each small box of paper weighs 50 pounds and each large box of paper weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Find :

Determine the number of small boxes shipped and the number of large boxes shipped.

Calculations :

Let "S" be small boxes and "L" be large boxes.

Small box + Large box = 19

50S + 80L = 1280

→ 5S + 8L = 128

→ 5 (19 - L) + 8L = 128

→ 3L = 128 - 95

→ L = 33/3

→ L = 11ㅤㅤ

Finding the small box:

→ S = 19 - L

→ S = 19 - 11

→ S = 8

Therefore ,

Large boxes = 11.

Small boxes = 8.

orrrrrr

The number of small boxes is 8 and that of the large boxes is 11.

Step-by-step explanation:

Each small box of paper weighs 50 pounds and each large box of paper

weighs 80 pounds. A total of 19 boxes of paper were shipped weighing 1280 pounds altogether.

Let there are x small boxes and y large boxes.

Then,

x + y = 19 ............ (1) and

50x + 80y = 1280

⇒ 5x + 8y = 128 ............... (2)

Now, solving equations (1) and (2) we get,

5( 19 - y) + 8y = 128

⇒ 3y = 128 - 95 = 33

⇒ y = 11

Now, from equation (1) we get, x = 19 - y = 19 - 11 = 8

Therefore, the number of small boxes is 8 and that of the large boxes is 11. (Answer)

8 0
2 years ago
Bruce is going to call one person from his contacts at random. He has 25 total contacts. 20 of those contacts are from his neigh
PtichkaEL [24]
No of people not from their neighborhood=25-20=5
total contact s=25
therefore probability to call a person not from his neighborhood=5/25=1/5
therefore P=1/5
5 0
3 years ago
Read 2 more answers
The sum of two numbers is 30. the first number is 1/5 of the second number. what are the numbers?
bonufazy [111]
Same question
x+y=30
x is 1/5 of y
x=y/5
subsitute
y/5+y=30
multily both sidse by 5
y+5y=150
add
6y=150
divide both sides by 6
y=25
subsitute
x=y/5
x=25/5
x=5
the numbers are 5 and 25

6 0
3 years ago
What is the measure in degrees of 8x if one angle is already 7x and 44.4 degrees?
Julli [10]
7x+8x+44.4=180

15x=44.4=180

15x=135.6

x=9.04°

so 8x=72.32° and the 7x is 63.28°
6 0
3 years ago
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
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