A car drives 16 miles south and then 12 miles west. What is the magnitude of the car's displacement?
1 answer:
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Answer:
Explanation:
Acceleration on a VT graph is the slope of the line at the given point. We can find the slope at 3 with Δy/Δx. This gives us (4-2)/(3-(-3)) which works out to be -3m/s^2
Answer:
0.005 m
Explanation:
length of steel (L°) = 12 m
initial temperature (T) = 16 degrees
expected temperature (T') = 50 degrees
We can find how large the gaps should be if the track is not to buckle when the temperature is as high as 50 degrees from the formula below
ΔL = ∝L°ΔT where
- ΔL = expansion / gap
- ∝ = linear expansion coefficient of steel =
- L° = initial length
- ΔT = change in temperature
ΔL = x 12 x (50-16) = 0.005 m