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olga_2 [115]
2 years ago
8

Help????????????????

Physics
1 answer:
Naddik [55]2 years ago
6 0

Answer:

23.5

Explanation:

Dunno how 2 explain but this is correct 4 sureeeeee.

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The rocket is fired vertically and tracked by the radar station shown. When θ reaches 66°, other corresponding measurements give
Flauer [41]

Answer:

velocity = 1527.52 ft/s

Acceleration = 80.13 ft/s²

Explanation:

We are given;

Radius of rotation; r = 32,700 ft

Radial acceleration; a_r = r¨ = 85 ft/s²

Angular velocity; ω = θ˙˙ = 0.019 rad/s

Also, angle θ reaches 66°

So, velocity of the rocket for the given position will be;

v = rθ˙˙/cos θ

so, v = 32700 × 0.019/ cos 66

v = 1527.52 ft/s

Acceleration is given by the formula ;

a = a_r/sinθ

For the given position,

a_r = r¨ - r(θ˙˙)²

Thus,

a = (r¨ - r(θ˙˙)²)/sinθ

Plugging in the relevant values, we obtain;

a = (85 - 32700(0.019)²)/sin66

a = (85 - 11.8047)/0.9135

a = 80.13 ft/s²

4 0
3 years ago
If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizon
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Answer:

The final position made with the vertical is 2.77 m.

Explanation:

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The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

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Therefore, the final position made with the vertical is 2.77 m.

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What is matter, atom, molecules?
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