Answer:
True
Explanation:
If a thin, spherical, conducting shell carries a negative charge, We expect the excess electrons to mutually repel one another, and, thereby, become uniformly distributed over the surface of the shell. The electric field-lines produced outside such a charge distribution point towards the surface of the conductor, and end on the excess electrons. Moreover, the field-lines are normal to the surface of the conductor. This must be the case, otherwise the electric field would have a component parallel to the conducting surface. Since the excess electrons are free to move through the conductor, any parallel component of the field would cause a redistribution of the charges on the shell. This process will only cease when the parallel component has been reduced to zero over the whole surface of the shell
According to Gauss law
∅ = EA =-Q/∈₀
Where ∅ is the electric flux through the gaussian surface and E is the electric field strength
If the gaussian surface encloses no charge, since all of the charge lies on the shell, so it follows from Gauss' law, and symmetry, that the electric field inside the shell is zero. In fact, the electric field inside any closed hollow conductor is zero
<u>Answer:
</u>
Distance traveled = 70 meters
Displacement = 36.06 meters
<u>Explanation:
</u>
Let north be positive Y and east be positive X
10 meters north, displacement = 10 j meters
20 meters west, displacement = -20 i meters
40 meters south, displacement = -40 j meters
Total displacement = (10 j - 20 i – 40 j) meters = (- 20 i - 30 j) meters
Magnitude of displacement = 
Distance traveled = 10+20+40 = 70 meters
Ok so this is simple projectile motion problem.
if we have an object falling in free fall it is subject to gravity of -9.80m/s^2
so it says it takes 6 sec to fall and we know initial velocity was zero so we know that h=vt+1/2gt^2 so we get h=0+1/2*9.80*6^2 = 176.4m
so solving for final speed we get KE=PE = 1/2mv^2=mgh = 1/2v^2=gh so
v=sqrt(2*g*h) = sqrt(2*9.8*176.4m) = 58.8m/s final speed when it hits the ground
hope this helps you! Thanks!!
Answer:
The discharge rate is 
Explanation:
From the question we are told that
The diameter is 
The head is 
The coefficient of contraction is 
The coefficient of velocity is 
The radius is mathematically evaluated as
substituting values
The area is mathematically represented as
substituting values
The discharge rate is mathematically represented as
substituting values
Answer:
the aircraft must travel at a speed of <em>73.4 m/s</em> in order to create the ideal lift.
Explanation:
We will use Bernoulli's theorem in order to determine the pressure lift:
ΔP = 1/2 (ρ)(v₂² - v₁²)
the generated pressure lift is ΔP = 1000 N/m²
Therefore,
1000 = 1/2(ρ)(v₂² - v₁²)
v₂² - v₁² = 2000 / ρ
v₂² = (2000 N/m² / 1.29 kg/m³) + (62 m/s)²
v₂ = √[ (2000 N/m² / 1.29 kg/m³) + (62 m/s)² ]
<em>v₂ = 73.4 m/s </em>
<em></em>
Therefore, the aircraft must travel at a speed of <em>73.4 m/s</em> in order to create the ideal lift.
