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nadezda [96]
4 years ago
15

Please answer the following on the pictureASAP PLZZZ

Chemistry
1 answer:
maxonik [38]4 years ago
3 0

30. Atomic Number is 17

31. Chlorine

32. 35.45

33. Nonmetal

34. 3 energy levels

35. 7 Valence electrons

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PLEASE HELP ME!!! WORTH 20 POINTS!!!
svlad2 [7]

Answer:

You need to heat the mixture to 78.37°C

Explanation:

In distillation, you can separate 2 or more compounds based on their difference in boiling points.

In a mixture of ethanol and water, in theory, you need to heat the mixture to 78.37°C. In this temperature, the ethanol must be evaporated and then condensed in the receiving flask.

5 0
4 years ago
When a theory is disproved by further evidence, which of the following occurs?
kati45 [8]
Answer: D. New data must be found to support it

When a theory is disproved by other further evidence, it is just proper to look for new data to support the theory until it is proven otherwise. It cannot be considered a failure right away but cannot be part of the scientifi knowledge too and more not to become a law. 
8 0
3 years ago
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Please help me with this
Svetradugi [14.3K]
The third one is the correct answer :)
6 0
3 years ago
Hello,
Ulleksa [173]

Answer:

In talc preparation, it is used during the filtration process and also acts as a distribution agent. When it is added to the dill water, it combines with all other compounds present in the substance and leaves the water alone. In this way, it acts as a filtering agent.

Explanation:

it has already been answered

8 0
3 years ago
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You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye
dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

V = 10 mL solution

V_{added} = 12.20 mL

V_{total} = 22.20 mL

then,

M 0.103 M of NaOH,

V_{rinsed} = experiment  will not be affected

V_{total \ base} = 10.38 mL

Now,

⇒  mol of NAOH = MV

                            = 0.103\times 10.38

                            =  1.06914  \ m

Whether Sulfuric acid, then

⇒  H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O

⇒  mol \ of \ acid =\frac{1}{2}\times \ mol \   of  \ base

⇒  1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid

Before any dilution:

V_{sample} = 10  \ mL

⇒  M \ acid = \frac{m \ mol}{V}

                 =\frac{ 0.53457 }{10}

                 =0.053457 \ M (Sulfuric acid)

6 0
3 years ago
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