<span>In the question ' which of the following most likely require intermolecular force', options A and C given are definitely not the correct answers. Among the items listed in the questions, the one that will most likely required an intermolecular force is a rock maintaing its solid shape. Thus, the correct option is B. Intermolecular forces are forces which maintain chemical interactions between molecules of a particular susbstance and other types of paticles that may be present in the substance. Rocks are made up of differet particles and their structures are held together by different types of intermolecular forces depending on the types of particles present in the rock. Intermolecular forces can only occur among molecules and other particles in a compound that is why the other two options are wrong. Intermolecular force can either be attractive or repulsive. Attraction occurs between molecules of opposite charges, that is, positive and negative charges while repulsion occurs between particles of like charges, for intstance, between positive and positive charges. The Intermolecular forces that exist in a compound maintaings the integrity of the structure of that compound. Intermolecular forces in compounds exist in different forms, we have electrovalent bonds, covalent bonds, hydrogen bond, vander waals forces, etc. The type of molecules that exist in a compound will determine the type of intermolecular forces that will exist among the molecules of that substance. Electrovalent bonds are the strongest type of intermolecular force and it normally exist between metals and non metals. Covalent bonds involved sharing of electrons among the participating elements while vander waals forces are the weakest form of intermolecular forces. Forces are often required to break intermolecular forces apart. Breaking the intermolecular forces apart will destroy the structure of the substance inlvolved.</span>
Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.
Explanation:
Given:
= 61 L,
= 183 K,
= 0.60 atm
At STP, the value of pressure is 1 atm and temperature is 273.15 K.
Now, formula used to calculate the new volume is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.
Answer: The number 4 indicates 4 electrons.
Explanation: We are given an electronic configuration, which is:

Here,
- The letters denote the sub-shells of an element.
- The numbers written before the letters which are 1, 2 and 2 represents the Principle Quantum Number and these represents the energy level of the sub-shells.
- The number which are written in the superscripts which are 2, 2 and 4 denotes the electrons which are present in the sub-shell.
Hence, 4 indicates 4 electrons present in 2p sub-shell.
Answer:
Zero
Explanation:
Recall that;
E = q + w
Where;
q = heat, w = work done
When heat is absorbed by the system q is positive
When heat is evolved by the system q is negative
When the system does work, w is negative
When work is done on the system w is positive
Step 1
ΔE1= 60 KJ + 40 KJ = 100KJ
Step 2
ΔE2= (-30 KJ) + (-70 KJ) = (-100) KJ
ΔE1 + ΔE2= 100KJ + (-100) KJ = 0KJ
Answer:
Explanation:
we know that
ΔH=m C ΔT
where ΔH is the change in enthalpy (j)
m is the mass of the given substance which is water in this case
ΔT IS the change in temperature and c is the specific heat constant
we know that given mass=2.9 g
ΔT=T2-T1 =98.9 °C-23.9°C=75°C
specific heat constant for water is 4.18 j/g°C
therefore ΔH=2.9 g*4.18 j/g°C*75°C
ΔH=909.15 j