Since there is a negative exponent, you need to first convert that into a positive exponent which is going to be 1/4^5
Then, we can find out the answer by simply breaking apart the exponents into 5 groups of 4.
1/(4)(4)(4)(4)(4)
Answer: B
Answer:
I assume AC = 49.89 since the number is cut off
Step-by-step explanation:
tangent(degree) = opposite / adjacent
To find AC, you can set up tan(29) = AC / CB
tan(29) = AC / 90 (the picture is cutted off, so I assume....)
= AC
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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The anwser would be -15
3 x (-5) = -15
