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4 years ago

camcorder has a power rating of 14 watts. If the output voltage from its battery is 3 volts, what current does it use?

1 answer:

3 0

Power rating tells you the amount of electricity a particular device like a camcorder needs. The power, voltage and current are all related using the equation: P = IV.

Therefore,

P = IV
I = P/V = 14 watts/3 volts = 4.67 A

Thus, the current must be 4.67 Amperes for the camcorder.

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How much kinetic energy does 2200kg car have if it is moving at 35m/s

Korolek [52]

Answer:1347500joules

Explanation:

Kinetic energy=(mass(velocity)^2)/2

Kinetic energy=(2200(35)^2)/2

Kinetic energy=(2200×1225)/2

Kinetic energy=2695000/2

Kinetic energy=1347500joules

5 0

4 years ago

You are climbing in the High Sierra when you suddenly find yourself at the edge of a fog-shrouded cliff. To find the height of t

s344n2d4d5 [400]

Answer:

Height with sound ignored = Gravity x Time taken = 9.8 x 8.60 = 84.28 meters

Time taken by the sound = 84.28/330 = 0.255 seconds

Height with sound involved = (84.28 x 0.255) + 84.28 = 105.80 meters

a. Underestimated

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3 years ago

The density of air at room temperature is about 1.2 g/L. This is the same as

Verdich [7]

The correct answer is
<span>C) 1200 g/m3.

Let's see why. The relationship between liters and cube decimeters is
</span> $1 L = 1 dm^3$
Therefore,
$1 g/L= 1 g/dm^3$
However, we also know that
$1 dm^3 = 10^{-3} m^3$
Therefore,
$1 L = 10^{-3} m^3$
and
$1 \frac{g}{L}= 1 \frac{g}{10^{-3} m^3} =1 \cdot 10^3 \frac{g}{m^3} =1000 \frac{g}{m^3}$

Therefore, the density of the problem $1.2 g/L$ becomes
$d=1.2 g/L=1200 g/m^3$

3 0

3 years ago

Which of the following point towards the center of the circle in uniform circular motion?

Luba_88 [7]

Answer: E) Acceleration, net force

Explanation: In order to explain this problem we have to consirer that the uniform circulat motion has constant angular velocity (ω) and the vector velocity is changed its direction for any point that cover the circle but its modulus is contant and its value is v=ω*R. In order to ensure these conditions, the net force also the accelaration called centripetal must point to the center of the circular trajectory.

5 0

4 years ago

In reading the instruction manual that came with your garagedoor opener, you see that the transmitter unit in your car produces

iVinArrow [24]

Answer:

0.09221 V/m

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

P = Power of transmitter = 250 mW

r = Distance to source = 42 m

c = Speed of light = $3\times 10^8\ m/s$

$E_0$ = Electric field amplitude

Intensity of a wave is given by

$I=\frac{P}{4\pi r^2}\\\Rightarrow I=\frac{250\times 10^{-3}}{4\pi \times 42^2}\\\Rightarrow I=1.12779\times 10^{-5}\ W/m^2$

Intensity is also given by

$I=\frac{E_0^2}{2\mu_0 c}\\\Rightarrow E_0=\sqrt{I2\mu_0 c}\\\Rightarrow E_0=\sqrt{1.12779\times 10^{-5}\times 2\times 4\pi \times 10^{-7}\times 3\times 10^8}\\\Rightarrow E_0=0.09221\ V/m$

The electric field amplitude at the receiver when it first fails is 0.09221 V/m

3 0

4 years ago