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3 years ago

13

What is #6 IM GIVING 40 POINTS

1 answer:

frosja888 [35]3 years ago

4 0

Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity. Its standard units are meters per second per second, or meters per second squared. (this is for number 3)

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Which of the following scientists taught physics in the United States?

Sergio039 [100]

<span>Subrahmanyan Chandrasekhar

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3 years ago

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The ball is moving at a constant speed of 0.5 m/s for 2.3 seconds how far does it go?

yarga [219]

Distance = (speed) x (time)

Distance = (0.5 m/s) x (2.3 s)

Distance = (0.5 x 2.3) m

Distance = 1.15 meters

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3 years ago

A 320 g air track cart traveling at 1.25 m/s collides with a stationary 270 g cart. What is the speed of the 270 g cart after th

Nutka1998 [239]

Answer:

The speed of the 270g cart after the collision is 0.68m/s

Explanation:

Mass of air track cart (m1) = 320g

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Mass of stationary cart (m2) = 270g

Velocity after collision (V) = m1u1/(m1+m2) = 320×1.25/(320+270) = 400/590 = 0.68m/s

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3 years ago

g calculate the effectiveness radiation dosage in sieverts for a 79 kg person who is exposed 6.8x10^9

Elza [17]

Answer:

The answer is " $\bold{dosage = 0.031 rem}$ "

Explanation:

please find the complete question in the attached file.

Given value:

$m = 79\ kg \\\\n = 3.4 \times 10^9 \\\\E = 5.5 \times 10^{-13} \\\\ RBE = 15$

$\to E = n E\\$

$= 3.4 \times 10^9 \times 5.5 \times 10^{-13} \\\\ = 1.87 \times 10^{-3}$

$\to E(absorbed) = 1.87 \times 10^{-3} \times 0.87 = 1.63 \times 10^{-3}$

calculating the radiation absorbed per kg:

$= \frac{1.63 \times 10^{-3}}{79} \\\\ = 2.06 \times 10^{-5} \\\\ = 0.00206 \ rad$

$\to Dosage = 0.00206 \times 15 \\$

$= 0.031 \ \ rem$

4 0

3 years ago

HELP!!!! WITH THIS PLSSS!!!

AlekseyPX

Answer:

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Explanation:

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3 years ago