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Sergio039 [100]
3 years ago
13

An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below

the wing is 199 m/s. The density of the air is 1.29 kg/m3. What is the lifting force on a wing of area 27.0 m2?
Physics
1 answer:
grin007 [14]3 years ago
6 0
<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let P be the pressure at a point.

Let p be the density fluid at a point.

Let v be the velocity of fluid at a point.

Bernoulli's equation states that P+\frac{1}{2}pv^{2}+pgh=constant for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let p_{up} be the pressure of a point just above the wing.

Let p_{do} be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}

So,p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa

Force is given by the product of pressure difference and area.

Given that area is 27ms^{2}.

So,lifting force is 16398.48\times 27=442758.96N

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Answer

In this question we have given,

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[tex]E1=(8.98755*10^9)*(40)/(2000-3000)^2\\

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[tex]E2=(8.98755*10^9)*(-40)/(2000-1000)^2\\

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Total electric feild E at the aircraft is given as

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\\E=359502+359502\\E= 719004V/m\\

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3 years ago
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Hello,

<span>A car with a mass of 2.0×10^3 kg is traveling at 15m/s. We need to find the momentum of the car. To do so, follow this formula:

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p=30000

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