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arsen [322]
3 years ago
6

a 4 kg bowling ball videos rolling down a lane at bowling alley at 6 m/s when the ball strikes the pins is moving your 5.1 m/sho

w much energy in the J is lost due to the friction?​
Physics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

19.98Joules

Explanation:

Energy possessed by the body is the kinetic energy

Kinetic Energy = 1/2mv²

m is the mass

v is the velocity

For the 4kg moving at 6m/s

kE = 1/2 * 4 * 6^2

KE = 1/2 * 4 * 36

KE = 72Joules

For the 4kg moving at 5.1m/s

kE = 1/2 * 4 * 5.1^2

KE = 1/2 * 4 *26.01

KE = 52.02Joules

Amount of Energy lost = 72 - 52.02

Amount of Energy lost = 19.98Joules

Hence the amount of Energy lost is 19.98Joules

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An empty parallel plate capacitor is connected between the terminals of a 18.8-V battery and charges up. The capacitor is then d
Basile [38]

Answer:

p.d' = 37.6 V

Explanation:

From the question we are told that:

Potential difference p.d=18.8V

New Capacitor C_1=C_2/2

Generally the equation for Capacitor capacitance is mathematically given by

C=\frac{eA}{d}

Generally the equation for New p.d' is mathematically given by

 C_2V=C_1*p.d'

  p.d' = 2V

 p.d'= 2 * 18.8

 p.d' = 37.6 V

7 0
3 years ago
Both the Moon and the Sun influence the tides on Earth. The moon has a much greater influence though. Why is that? A) because th
Temka [501]
C. The sun is 400 times farther from Earth than the moon is.
3 0
3 years ago
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How does work affect energy between objects so it can cause a change in the form of energy? Work transfers energy. Work changes
IceJOKER [234]

'Doing work' is a way of transferring energy from one object to another, energy is transferred when a force moves through a distance.

If i explain with formula

Work done (J) = Energy transferred (J)

So more energy, more work done bc u transferred more energy to move the object and doing the work. and if you only use a little of energy, the work done also only a little.

4 0
3 years ago
When does the autumnal equinox occur in the Southern Hemisphere?
Svetlanka [38]
All answers to the Earth Science, Meteorology: Part 1 Unit Test
1. B. March 21
2. D. December 21
3. B. They move faster.
4. C. 300,000 kilometers per second
5. B. Conduction
6. A. longer than those emitted by the sun
7. D. Water vapor and carbon dioxide
8. C. Scattering
9. D. Both b and c
10. C. There is a greater percentage of water surface in the Sourhern Hemisphere
11. D. Both a and b
12. B. Absorbing outgoing radiation
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3 0
3 years ago
A compound microscope has an objective lens of focal length 1.40 cm and an eyepiece with a focal length of 2.20 cm. The objectiv
olchik [2.2K]

Answer:

magnification is - 159

objective distance is 3.85 cm

Explanation:

Given data

focal length f1 = 1.40 cm

focal length f2 = 2.20 cm

separated d = 19.6 cm

to find out

angular magnification and How far from the objective

solution

we know magnification formula that is

magnification = ( - L / f1 ) (D/f2)

here D = 25 cm put all value

magnification = ( - 19.6 / 1.40 ) (25/2.20)

magnification = - 159

and

now we apply lens formula

i/f = 1/q + 1/p

p = f2 = 2.20

so

q = f2 p / p -f2

q = 1.4(2.20) / ( 2.2 - 1.4 )

q = 3.85 cm

so objective distance is 3.85 cm

3 0
3 years ago
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