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2 years ago

Is ratus a weather related word?

Chemistry

1 answer:

katen-ka-za [31]2 years ago

6 0

In most cases it is.

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25. What is the molarity of an H2SO4 solution if

gizmo_the_mogwai [7]

Answer:

Explanation:

hope it helps:)

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7 0

1 year ago

After creating a definition for what it means to be sexually abstinent, list reasons why being abstinent is important for you an

Sever21 [200]

Sexually abstinent: refraining from some or all sexual activities
school (higher education)
health (stds)
pregnancy (not ready for children)

5 0

2 years ago

A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2

Mila [183]

From the calculations, the concentration of the acid is 0.24 M.

<h3>What is neutralization?</h3>

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA = 50 mL

VB = 20 mL

NA = 1

NB = 2

CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

Learn more about neutralization:brainly.com/question/27891712

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5 0

1 year ago

How is reusable water bottles are more environmentally friendly than one use water bottle?

dexar [7]

Answer:

They are better because they are more usable than Plastic and reusable water bottles are better for the planet!

Explanation:

6 0

2 years ago

An archaeologist graduate student found a leg bone of a large animal during the building of a new science building. The bone had

Vlad [161]

Answer : The time passed in years is $2.74\times 10^2\text{ years}$

Explanation :

Half-life of carbon-14 = 5730 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5730\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = initial amount of the reactant disintegrate = 15.3

a - x = amount left after decay process = 14.8

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{15.3}{14.8}$

$t=274.64\text{ years}=2.74\times 10^2\text{ years}$

Therefore, the time passed in years is $2.74\times 10^2\text{ years}$

4 0

2 years ago