Is ratus a weather related word?

What is the nuclear binding energy of an atom that has a mass defect of 5.0446

notsponge [240]

Answer:

Option C: 4.54 x $10^{11}$ KJ/mol of nuclei

Note: Here in this question option C is not correctly put. It is 4.54 x $10^{11}$ rather than 4.54 x $10^{-123}$ .

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x $10^{-27}$

Because 1 amu = 1.6606 x $10^{-27}$ Kg.

Mass defect = 8.383 x $10^{-27}$ kg.

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x $10^{8}$ m/s²

E = (8.383 x $10^{-27}$ ) x (3.00 x $10^{8}$ )²

E = 7.54 x $10^{-10}$ J this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x $10^{-10}$ Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x $10^{23}$ nuclei/mol) =

4.54 x $10^{11}$ kJ/mol of nuclei .

E = 4.54 x $10^{11}$ kJ/mol of nuclei . So, this is the nuclear binding energy of that atom, which is option C.

Note: Here in this question option C is not correctly put. It is 4.54 x $10^{11}$ rather than 4.54 x $10^{-123}$

4 0

3 years ago

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shepuryov [24]

Answer:

Explanation:

All three lighter boron trihalides, BX3 (X = F, Cl, Br), form stable adducts with common Lewis bases. Their relative Lewis acidities can be evaluated in terms of the relative exothermicities of the adduct-forming reaction. Such measurements have revealed the following sequence for the Lewis acidity: BF3 < BCl3 < BBr3 (in other words, BBr3 is the strongest Lewis acid).

This trend is commonly attributed to the degree of π-bonding in the planar boron trihalide that would be lost upon pyramidalization (the conversion of the trigonal planar geometry to a tetrahedral one) of the BX3 molecule, which follows this trend: BF3 > BCl3 > BBr3 (that is, BBr3 is the most easily pyramidalized). The criteria for evaluating the relative strength of π-bonding are not clear, however. One suggestion is that the F atom is small compared to the larger Cl and Br atoms, and the lone pair electron in the 2pzorbital of F is readily and easily donated, and overlaps with the empty 2pz orbital of boron. As a result, the [latex]\pi[/latex] donation of F is greater than that of Cl or Br. In an alternative explanation, the low Lewis acidity for BF3 is attributed to the relative weakness of the bond in the adducts F3B-L.

3 0

2 years ago

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A solution is prepared by dissolving 8.75 grams of sodium chloride in enough volume of water to produce 112.0 grams of the NaCl

ICE Princess25 [194]

Answer : The percent by mass of the solution is 7.81 %

Explanation : Given,

Mass of NaCl = 8.75 g

Mass of solution = 112.0 g

Now we have to determine the percent by mass of the solution.

$\text{Mass percent}=\frac{\text{Mass of NaCl}}{\text{Mass of solution}}\times 100$

Putting values in above equation, we get:

$\text{Mass percent}=\frac{8.75g}{112.0g}\times 100=7.81\%$

Therefore, the percent by mass of the solution is 7.81 %

6 0

3 years ago

Based on these ideas, what are the pro's and con's for both Sexual Reproduction and Asexual reproduction?

Svetradugi [14.3K]

Asexual
Pro:
1. inexpensive to make offspring (usually make a lot at a time and not invest a lot of time in raising them).
2. Do not need a mate to reproduce.
3. Can rapidly expand a population
Con:
1. genetically identical- prone to extinction because once a parasite has evolved to attack a specific genotype, it can kill them all.
2. Lineages usually don't last longer than a couple thousand years

Sexual:
Pros:
1. Genetically unique- so more likely to create a "successful" offspring
2. Lineages more likely to last hundreds of thousands of years

Cons:
1. More effort into creating offspring- require more parental effort
2. STD's- easily to pass
3. need to find a mate or else won't be successful as an organism.

Hope this helps you.

6 0

3 years ago

An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average

Deffense [45]

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = $\frac{Displacement }{Change in time}$ = Δx / Δt = $\frac{x2 - x1}{t2 - t1}$