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PtichkaEL [24]
3 years ago
13

Convert 512 kilograms to milligrams. 0.000512 0.512 512,000 512,000,000

Chemistry
2 answers:
denpristay [2]3 years ago
8 0

<u>Answer:</u> The correct answer is 512,000,000

<u>Explanation:</u>

We are given:

A quantity having value 512 kilograms

To convert this value into milligrams, we use the conversion factor:

1 kg = 1,000,000 mg

Converting the given value into milligrams, we get:

512kg\times \frac{1,000,000mg}{1kg}=512,000,000mg

Hence, the correct answer is 512,000,000

olga55 [171]3 years ago
5 0
The answer is D! 512000000
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At 300.0 K and 0.987 atm pressure, what will be the volume of 2.30 mol of Ne?
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Answer:

V = 57.39 L

Explanation:

Given that,

Temperature, T = 300 K

Pressure, P = 0.987 atm

No. of moles of Ne, n = 2.30 mol

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PV = nRT

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3 years ago
Consider the equation: 2NO2(g) N2O4(g). Using ONLY the information given by the equation which of the following changes would in
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g A radioactive isotope of mercury, 197Hg, decays to gold, 197Au, with a disintegration constant of 0.0108hrs.-1. What % of the
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Answer:

7.49% of Mercury

Explanation:

Let N₀ represent the original amount.

Let N represent the amount after 10 days.

From the question given above, the following data were obtained:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Next, we shall convert 10 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

10 days = 10 day × 24 h / 1 day

10 days = 240 h

Thus, 10 days is equivalent to 240 h.

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Log (N₀/N) = kt /2.303

Log (N₀/N) = 0.0108 × 240 /2.303

Log (N₀/N) = 2.592 / 2.303

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Take the anti log of 1.1255

N₀/N = anti log 1.1255

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Thus, 7.49% of Mercury will be remaining after 10 days

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2 years ago
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