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PtichkaEL [24]
3 years ago
13

Convert 512 kilograms to milligrams. 0.000512 0.512 512,000 512,000,000

Chemistry
2 answers:
denpristay [2]3 years ago
8 0

<u>Answer:</u> The correct answer is 512,000,000

<u>Explanation:</u>

We are given:

A quantity having value 512 kilograms

To convert this value into milligrams, we use the conversion factor:

1 kg = 1,000,000 mg

Converting the given value into milligrams, we get:

512kg\times \frac{1,000,000mg}{1kg}=512,000,000mg

Hence, the correct answer is 512,000,000

olga55 [171]3 years ago
5 0
The answer is D! 512000000
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Total density of filled ball with nitrogen gas: \frac{0.12G+0.6524g}{0.560L} = 1.3792g/L

The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d). The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air. Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = d_4=1.165g/L

Mass of the nitrogen gas : 1.165g/L \times 0.560L = 0.6524g

Learn more about Mass and Density here:

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What is the mass number of an isotope with an atomic number of 57 and that has 69 neutrons?
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mass number=126

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What is the part of the cartridge that actually flies outward (the projectile)?
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the culotte, the fulminant capsule and the sheath or cap together with remains of powder

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For a particular reaction, ΔH=−111.4 kJ/mol and ΔS=−25.0 J/(mol·K).
PtichkaEL [24]
That’s the answer ^^^^
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3 years ago
Hydrofluoric acid, hf, has a ka of 6.8 × 10−4. what are [h3o+], [f−], and [oh−] in 0.710 m hf?
STALIN [3.7K]

Answer:

[H₃O⁺] = [F⁻] = 2.2 x 10⁻² M. & [OH⁻] = 4.55 x 10⁻¹³.

Explanation:

  • For a weak acid like HF, the dissociation of HF will be:

<em>HF + H₂O ⇄ H₃O⁺ + F⁻.</em>

[H₃O⁺] = [F⁻].

<em>∵ [H₃O⁺] = √Ka.C,</em>

Ka = 6.8 x 10⁻⁴, C = 0.710 M.

∴ [H₃O⁺] = √Ka.C = √(6.8 x 10⁻⁴)(0.710) = 2.197 x 10⁻² M ≅ 2.2 x 10⁻² M.

<em>∴ [H₃O⁺] = [F⁻] = 2.2 x 10⁻² M.</em>

<em></em>

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

<em>∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺]</em> = 10⁻¹⁴/(2.2 x 10⁻²) = <em>4.55 x 10⁻¹³.</em>

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