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3 years ago

HELP PLZZZ !! 3. Solve the equation by factoring. C^2 - 4c = 0

Mathematics

2 answers:

sashaice [31]3 years ago

6 0

C^2 - 4c = 0

c(c-4) = 0

c-4=0
c=4

c = 0 or 4

prohojiy [21]3 years ago

5 0

Answer:

0,4

Step-by-step explanation:

See image below:)

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Which graph represents the division of -12 / 4 ?

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The top graph represents the division of -12/4

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3 years ago

Find the circumference of the object. Use 3.14 or 22/7

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C=2pi r
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3 years ago

A baseball diamond has an area of 3,600 ft. square. What is the distance between each base.

snow_lady [41]

Answer:

A diamond is the same thing as a square. So the side lengths are all the same. Multiplied length by width you get area. So square the area (3600) and you get 60 feet side length. The bases are 60 feet away from each other.

SLOVIN

A baseball diamond is just like a square, meaning the area of the baseball diamond can be calculate with: , where s = side, and A = area.

Plug in area value.

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2 years ago

Read 2 more answers

A local golf course charges members $35 an hour for the first four hours, $40 an hour for the next fou

Slav-nsk [51]

Answer:

Step-by-step explanation:

35x4 =140

40x4=160 +

----------------

300$ all together

Hope this helps

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3 years ago

A bridge is built in the shape of a parabolic arch. The bridge arch has a span of 166 feet and a maximum height of 40 feet. Find

scoray [572]

Answer:

38.27775 feet

Step-by-step explanation:

The bridge has been shown in the figure.

Let the highest point of the parabolic bridge (i.e. vertex of the parabola) be at the origin, $O(0,0)$ in the cartesian coordinate system.

As the bridge have the shape of an inverted parabola, so the standard equation, which describes the shape of the bridge is

$x^2=4ay\;\cdots(i)$

where $a$ is an arbitrary constant (distance between focus and vertex of the parabola).

The span of the bridge = 166 feet and

Maximum height of the bridge= 40 feet.

The coordinate where the bridge meets the base is $A(83, -40)$ and $B(-83, -40).$

There is only one constant in the equation of the parabola, so, use either of one point to find the value of $a$ .

Putting $A(83,-40)$ in the equation (i) we have

$83^2=4a(-40)$

$\Rightarrow a=-43.05625$

So, on putting the value of $a$ in the equation (i), the equation of bridge is

$x^2=-172.225y$

From the figure, the distance from the center is measured along the x-axis, x coordinate at the distance of 10 feet is, $x=\pm 10$ feet, put this value in equation (i) to get the value of y.