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professor190 [17]
3 years ago
13

Let sin(2x) = cos(x), where 0° ≤ x < 180°. What are the possible values for x?

Mathematics
2 answers:
lions [1.4K]3 years ago
6 0

Answer:

The possible values of x are 90°, 30° and 150°.

Step-by-step explanation:

Given that,

sin(2x) = cos(x) where 0° ≤ x < 180°

We know that, sin(2x) = 2 sinx cosx

2 sinx cosx = cosx

Subtract cosx on both sides

2 sinx cosx - cosx = 0

cosx (2sinx-1)=0

It means, cosx = 0 and (2sin x -1 ) = 0

cos x = cos0           and        sinx = 1/2

x = 90°                     and        x = 30°, 150°

Hence, the possible values of x are 90°, 30° and 150°.

ollegr [7]3 years ago
4 0

Answer:

For those too lazy to read answer above, it's D.

Step-by-step explanation:

Edge2021

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Answer:

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Step-by-step explanation:

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Solution

a^2 + b^2 = 51^2                      Substitute for b^2 = h^2

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