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3 years ago

9

Can someone please explain how to solve 2.7÷0.8 step by step please

2 answers:

VMariaS [17]3 years ago

6 0

Answer: 3 and 3/8 or 27/8

Step-by-step explanation:

First step, you will need to move the decimal to the side by 1 place value.

0.8 --> 8. and 2.7--> 27.

Then just do your normal dividing.

27/8 = 3 and 3/8

The answer to 2.7÷0.8 can be either a mixed number or an improper fraction.

ololo11 [35]3 years ago

6 0

You have to move the decimal places to the right as many times as you need in order to make the number a while number you move the decimal place the same times as you did to the number outside the box which makes is 8 divided by 27 8 can’t go into 2 so u add a 0 and 8 can go into 27 3 times. You add a decimal point and subtract 24 from 27 u get 3 then you add a decimal point with a 0 8 can go into 30 3 times so it’s 6 add a decimal point to make it 60. Then 8 can go into 60 7 times subtract 56 from 60 and you get 4 add a decimal point and you get 40 8 can go into 40 5 times and your answer is 3.375

I added picture so u can see how it looks when you do it.

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3 years ago

The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

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$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

8 0

3 years ago

NEED HELP ASAP!

mote1985 [20]

Answer:

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Step-by-step explanation:

You input will always be your x so you just substitute x with 10 and simplify. Which is 30 minus 6, thus 24. :)

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3 years ago

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