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Arlecino [84]
3 years ago
9

Can someone please explain how to solve 2.7÷0.8 step by step please​

Mathematics
2 answers:
VMariaS [17]3 years ago
6 0

Answer: 3 and 3/8 or 27/8

Step-by-step explanation:

First step, you will need to move the decimal to the side by 1 place value.

0.8 --> 8. and 2.7--> 27.

Then just do your normal dividing.

27/8 = 3 and 3/8

The answer to 2.7÷0.8 can be either a mixed number or an improper fraction.

ololo11 [35]3 years ago
6 0

You have to move the decimal places to the right as many times as you need in order to make the number a while number you move the decimal place the same times as you did to the number outside the box which makes is 8 divided by 27 8 can’t go into 2 so u add a 0 and 8 can go into 27 3 times. You add a decimal point and subtract 24 from 27 u get 3 then you add a decimal point with a 0 8 can go into 30 3 times so it’s 6 add a decimal point to make it 60. Then 8 can go into 60 7 times subtract 56 from 60 and you get 4 add a decimal point and you get 40 8 can go into 40 5 times and your answer is 3.375

I added picture so u can see how it looks when you do it.

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Suppose a simple random sample of size nequals 150 is obtained from a population whose size is Upper N equals 30 comma 000 and w
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(a) Correct answer is Approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10.

(b) The value of P (X ≥ 770) is 0.0143.

(c) The value of P (X ≤ 720) is 0.0708.

Let X = number of elements with a particular characteristic.

The variable p is defined as the population proportion of elements with the particular characteristic.

The value of p is:

p = 0.74.

A sample of size, n = 1000 is selected from a population with this characteristic.

(a)

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

               μ = p

The standard deviation of this sampling distribution of sample proportion is:

                  σ = \sqrt \frac{p(1-p)}{n}

The sample selected is of size, n = 1000 > 30.

Thus, according to the central limit theorem the distribution of  is Normal, i.e. .

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Thus the correct option is (A).

(b) We need to compute the value of P (X ≥ 770).

Apply continuity correction:

P (X ≥ 770) = P (X > 770 + 0.50)

                  = P (X > 770.50)

Then,

   p > 770.5/1000 = 0.7705

Compute the value of  P( p > 0.7705) as follows:

P( p > 0.7705) = P(p -μ/σ > 0.7705 - 0.74/0.0139)

                       = P( Z > 2.19)

                       = 1 - P( Z< 2.19)

                       = 1 - 0.98574

                       = 0.01426

                       ≈ 0.0143

Thus, the value of P (X ≥ 770) is 0.0143.

(c)

We need to compute the value of P (X ≤ 720).

Apply continuity correction:

P (X ≤ 720) = P (X < 720 - 0.50)

                  = P (X < 719.50)

Then

Compute the value of  as follows:

P( p < 0.7195) = P(p -μ/σ > 0.7705 - 0.74/0.0139)

                       = P(Z < - 1.47)

                       = 1 - P(Z < 1.47)

                       = 1 - 0.92922

                       = 0.07078

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Thus, the value of P (X ≤ 720) is 0.0708.

Learn more about Simple Random sample:

brainly.com/question/13219833

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