PLEASE HELP ASAP PLEASE!!!!

Mathematics

1 answer:

malfutka [58]1 year ago

5 0

Answer:

(3,2)

Step-by-step explanation:

2x-4=y

2y+3x=13

We substitute the y in. They already gave us the equation 2x-4=y simplified so you would just plug this into the other equation

2(2x-4) +3x=13 : *distribute*

4x-8+3x=13 : *combine like terms*

7x-8=13 * add the 8 to the other side*

7x=21 *divide*

x=3

So the y=2x-4 is what we added in the place of the y to subtract it and solve for x. The second step would be solving for y. So now that we have our answer, 3 we plug it into the other equation preferably.

2(3)-4 =y : 6-4=y : 2=y

We can check our answer by pugging both x and y into both equations to make sure they are right. The statement should be true.

2x-4=y 2(3)-4=(2) 2=2

2y+3x=13 2(2)+3(3)=13 13=13

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What is the binomial expansion of (x 2y)7? 2x7 14x6y 42x5y2 70x4y3 70x3y4 42x2y5 14xy6 2y7 x7 14x6y 42x5y2 70x4y3 70x3y4 42x2y5

AysviL [449]

You can take x = a, 2y = b and then can apply the binomial theorem.

The expansion of given expression is given by:

Option D: $x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7$ is

<h3>What is binomial theorem?</h3>

It provides algebraic expansion of exponentiated(integer) binomial.

According to binomial theorem,

$(a+b)^n = \sum_{i=0}^n ^nC_i a^ib^{n-i}$

<h3>How to use binomial theorem for given expression?</h3>

Taking a = x, and b =2y, we have n = 7, thus:

$(x+2y)^7 = \: ^7C_0x^0(2y)^7 + \: ^7C_1x^1(2y)^6 + \: ^7C_2x^2(2y)^5 + \: ^7C_3x^3(2y)^4 + \:^7C_4x^4(2y)^3 + \:^7C_5x^5(2y)^2 + \:^7C_6x^6y^1 + \: ^7C_0x^7y^0\\\\
(x+2y)^7 = 128y^7 + 448xy^6 + 672x^2y^5 + 560x^3y^4 + 280x^4y^3 + 84x^5y^2 + 14x^6y + x^7\\\\
(x+2y)^7 = x^7 + 14x^6y + 84x^5y^2 + 280x^4y^3 + 560x^3y^4 + 672x^2y^5 + 448xy^6 + 128y^7$