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sladkih [1.3K]
3 years ago
9

A car with a constant velocity of 22 m/s is driven for 6.8 s. How far did it travel? (v =∆ d/∆t)

Physics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

C. 150 m

Explanation:

22 m/s x 6.8 = 149.6

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On my bike I was able to travel 40 miles in one hour from this information we can determine the bikes
valentinak56 [21]
You have a distance and a time so you can work out the bikes speed which would be distance/time so 40mph.
4 0
3 years ago
The standard wave format for any wave is wave. When depicting wave in standard wave format, the direction of motion must be rota
german

Answer:

Transverse wave  and Longitudinal wave  and Electromagnetic wave

Explanation:

  • An inverted wave is a wave in which the vibrations of the particles are perpendicular to the direction of wave motion.
  • Longitudinal waves, on the other hand, are waves in which the vibrations of the particles are parallel to the direction of wave motion.
  • Electromagnetic waves are waves that do not require medium media for transmission, including radio waves, microwaves, UV lights, etc.
  • Most electromagnetic waves are transverse in nature.
4 0
3 years ago
What is the acceleration of a 7 kg mass if the force of 70 N is used to move it toward the Earth?
Assoli18 [71]

Answer:

<h2>10 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

m is the mass

f is the force

From the question we have

a =  \frac{70}{7}  = 10 \\

We have the final answer as

<h3>10 m/s²</h3>

Hope this helps you

4 0
3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 10 rev/s. If such a star has a radius of 18 k
Aleks [24]

Answer:

mass of the neutron star =3.45185×10^26 Kg

Explanation:

When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.

That is

\frac{GM_{ns}}{R^2}= \omega^2 R

M_ns = mass odf the netron star.

G= gravitational constant = 6.67×10^{-11}

R= radius of the star = 18×10^3 m

ω = 10 rev/sec = 20π rads/sec

therefore,

M_{ns}= \frac{\omega^2R^3}{G} = \frac{4\pi^2\times(18\times10^3)^3}{6.67\times10^{-11}}

= 3.45185... E26 Kg

= 3.45185×10^26 Kg

4 0
3 years ago
How much force does it take to bring a 1,375 N car from rest to a velocity of 26 m/s in 6 seconds?
V125BC [204]

Explanation:

<u>Mass of car</u> = 137.5 kg

<u>Acceleration</u> = v - u / t = 26 - 0 / 6 = 4.33 m/sec^2

Force = m * a = 137.5 * 4.33 = 595.3 N

6 0
3 years ago
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