Answer:

See explanation below.
Step-by-step explanation:
For this case we define first some notation:
A= A new training program will increase customer satisfaction ratings
B= The training program can be kept within the original budget allocation
And for these two events we have defined the following probabilities

We are assuming that the two events are independent so then we have the following propert:

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

And using the De Morgan laws we know that:

So then we can write the probability like this:

And using the complement rule we can do this:

Since A and B are independent we have:

And then our final answer would be:

Answer:
(x-4)^2 + (y-3)^2 =8
Step-by-step explanation:
The midpoint of the diameter is (6+2)/2= 4, (5+1)/2 = 3
(4,3)
The radius is the distance from the midpoint to an endpoint
This is 2sqrt(8)
So the equation is
(x-4)^2 + (y-3)^2 =8
Answer:
x = 20
Step-by-step explanation:
Since there's 2 lines intercepting each other, the angle opposite of the other is the same.
3(20) + 50 = 110
6(20) - 10 = 110
Answer:
Two possible solutions
Step-by-step explanation:
we know that
Applying the law of sines

we have



step 1
Find the measure of angle A

substitute the values


The measure of angle A could have two measures
the first measure------->
the second measure ----->
step 2
Find the first measure of angle C
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 3
Find the first length of side c

substitute the values


therefore
the measures for the first solution of the triangle are
, 
, 
, 
step 4
Find the second measure of angle C with the second measure of angle A
Remember that the sum of the internal angles of a triangle must be equal to
substitute the values
step 5
Find the second length of side c

substitute the values


therefore
the measures for the second solution of the triangle are
, 
, 
, 