Answer:
14.63% probability that a student scores between 82 and 90
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a student scores between 82 and 90?
This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So
X = 90
has a pvalue of 0.9649
X = 82
has a pvalue of 0.8186
0.9649 - 0.8186 = 0.1463
14.63% probability that a student scores between 82 and 90
Answer:
There is sufficient evidence. A further explanation is provided below.
Step-by-step explanation:
According to the question,
The alternative as well as null hypothesis will be:
The test statistics will be:
⇒ 
By putting the values, we get
⇒ 
⇒ 
⇒ 
Or,
The p-value will be:
= 0.0071
i.e.,
⇒ 
Thus the above is the correct answer.
To get the Y values use the equation Y = MX and substitute the X and M values So for the first one you would get Y = -3 x -1 leaving Y as 3 then for the second you do Y = -3 x 0 giving you Y = 0 the third would be Y = -3 x 1 so Y would be -3 and you give the last one a shot >.O best of luck!
Answer:it will not
Step-by-step explanation:
Answer:
the outlier is the point at 15
the data is skewed to the bottom because the values below the median are far more spread out; there are more extreme values that are far below the median than above the median.
Step-by-step explanation:
