The <span>hardy-weinberg equation is
p2 + 2pq + q2 = 1
where are already given with
c = 0.1 and C = 0.9
SO
p2 = 0.9^2
p2 = 0.81
q2 = 0.01
0.81 + 2pq - 0.01 = 1
2pq = 0.18
The answers are
CC = 0.81
cc = 0.01
Cc = 0.18</span><span />
The second option: meiosis and fertilization
process A is meiosis, you can see that the gamete(haploid cell) results from the diploid cell. The gamete has n chromosomes(39), whereas the diploid cell has 2n(78)
process B is fertilization the two gametes(haploid) fuse together to form the zygote(diploid)
Answer:
d. Ao x oo
Explanation:
The other crosses with A would all result in complete dominance because the alleles (other than A) from the other parent are dominant. Because option D. crosses a h o m o zygous parent with a recessive trait, the cross could produce a child with blood type A.