There are two ways to solve this question.
1) To solve this question, we need to substitute a = 6 and b = -3 into the given expression and then evaluate:
(-a)(b)(-a + b)
= (-6)(-3)(-6 + (-3))
= 18(-9)
= -162
2) An alternative method is to simplify (-a)(b)(-a + b) into an expression without brackets and then substitute a = 6 and b = -3:
1. (-a)(b)(-a + b)
= (-ab)(-a + b)
= -ab*(-a) + (-ab)*b
= a^(2)b+ (-ab^(2))
= a^(2)b - ab^(2)
2. a^(2)b - ab^(2)
= 6^(2)*(-3) - 6*(-3)^2
= 36*(-3) - 6*9
= -108 - 54
= -162
The key to either method is to be careful with placement of brackets, especially where there are negative values involved.
Divide both sides by 2
|x-3|>4 and |x-3|<-4
ok so |x-3|<-4 is false, since |x|≥0 always
so we have
|x-3|>4
now assume
x-3>4 and
x-3<-4
x-3>
add 3
x>7
x-3<-4
add 3
x<-1
so
-1>x and x>7
so basically it is all numbers from -∞ to +∞ except from -1 to 7
in interval notaion
(-∞,-1)U(7,∞)
S={x|x<-1 or x>7}
Answer:
3x^2+5
Step-by-step explanation:
f(x) = 3x + 2 ; g(x) = x^2+ 1
(fºg)(x) = 3(x^2+ 1)+2
(fºg)(x) = 3x^2+3+2
(fºg)(x) = 3x^2+5
Answer:
Step-by-step explanation:
Enter your x and y values into your equation from your table
Answer:
two raised to the power of -3
Two to the power of negative 3
Step-by-step explanation:
1 divided by 2 to the power of 3