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sweet-ann [11.9K]
3 years ago
6

Using deionized water and sugar, prepare four standard solutions with 5.0, 10.0, 15.0 and 20.0 mass percent sugar concentrations

. Determine the density of each solution as well as that of the deionized water.
Empty Container 5 ml + container 10 ml + container 15 ml + container
Deionized water (g) 41.672 46.581 51.499 56.444
5.00% solution 37.557 42.623 47.675 52.731
10% solution 41.648 46.797 51.924 57.041
15% solution 37.572 42.840 48.099 53.372
20% solution 37.364 42.737 48.118 53.500

Using these five data points, create your own calibration curve, with x axis being the mass percent and the y axis being the density.
Chemistry
1 answer:
natulia [17]3 years ago
7 0

Answer:

Following are the solution to these question:

Explanation:

Please find the complete question in the attached file.

In point 1:

The information collected was given in the excel spreadsheet.

In point 2:

Each solution mass, Mass=Solution mass - empty container mass, was measured utilizing shape.

In point 3:

The density of each formula, density = \frac{mass\  (g)}{ volume \ was \ calculated \ in \ (mL)}

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chubhunter [2.5K]
Reaction of Cu(NO₃)₂ with each salt is as follow, 

1) with KNO₃;

                  Cu(NO₃)₂  +  KNO₃   →   Cu(NO₃)₂  +  KNO₃

Both salt products are water soluble.

2) With CuSO₄;

                  Cu(NO₃)₂  +  CuSO₄   →   CuSO₄  +  Cu(NO₃)₂
Again both Salt products are water soluble.

3) With K₂SO₄;

                  Cu(NO₃)₂  +  K₂SO₄   →  CuSO₄  +  2 KNO₃
Again both salt products are water soluble.

4) With K₂S;

                  Cu(NO₃)₂  +  K₂S   →   CuS  +  2 KNO₃
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Result:
           Option-4 is the correct answer.
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2) Solubility is how much solvent will dissolve in solute.

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Answer:

47.5 g of water can be formed

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This is the reaction:

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As ratio is 1:2, I will produce the double of moles of water, with the moles of methane I have.

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A compound's empirical formula tells you what the smallest whole number ratio between the atoms that make up that compound is.

I think of the empirical formula as a building block for molecules. A compound's molecular formula will depend on how many building blocks are needed to build a molecule of a given substance.

In your example, you know that the empirical formula of the compound is

NO

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This tells you that the minimum ratio between nitrogen atoms and oxygen atoms is

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molecular formula

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So, how would you determine how many building blocks you need? Well, start by figuring out the molar mass of one building block, i.e. the molar mass of the empirical formula.

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(

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