Answer:
a. 6 moles of O₂
b. 4.06×10²⁴ molecules of O₂
c. 3.04 g of KCl
Explanation:
Reaction of decomposition is:
2KClO₃ → 2KCl + 3O₂
a. See stoichiometry value
2 moles of potassium chlorate can decompose to 2 moles of potassium chloride and 3 moles of oxygen. Ratio is 2:3
If 2 moles of KClO₃ can decompose to 3 moles of O₂
Then 4 moles, may decompose to (4 . 3)/2 = 6 moles of O₂
b. In this case, the stoichiometry is the same.
Per 2 moles of KClO₃, I produce 2 moles of KCl
Then, 4.5 moles of KCl, were produced by 4.5 moles of KClO₃
We apply, the last relation:
(4.5 . 3) /2 = 6.75 moles of O₂ are also produced.
How many molecules are in 6.75 moles?
6.75 mol . 6.02×10²³ molecules/mol = 4.06×10²⁴ molecules of O₂
c. First of all, we convert the mass to moles:
5g . 1mol /122.55g = 0.0408 moles of salt
As ratio is 2:2, 0.0408 moles of salt, decompose to 0.0408 moles of KCl
We convert the moles to mass: 0.0408 mol . 74.55g /mol = 3.04g
= 25 g solution