Answer: 20L of H2O
Explanation:
C3H8 + 5O2 → 3CO2 + 4H2O
Recall 1mole of a gas contains 22.4L at stp
5moles of O2 contains = 5 x 22.4 = 112L
4moles of H2O contains = 4 x 22.4 = 89.6L
From the equation,
112L of O2 produced 89.6L H2O
There for 25L of O2 will produce XL of H2O i.e
XL of H2O = (25 x 89.6)/112 = 20L
Answer:
22.44°C will be the final temperature of the water.
Explanation:
Heat lost by tin will be equal to heat gained by the water

Mass of tin = 
Specific heat capacity of tin = 
Initial temperature of the tin = 
Final temperature =
=T

Mass of water= 
Specific heat capacity of water= 
Initial temperature of the water = 
Final temperature of water =
=T



On substituting all values:

we get, T = 22.44°C
22.44°C will be the final temperature of the water.