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photoshop1234 [79]
3 years ago
10

Which is the electron configuration for bromine?

Chemistry
1 answer:
murzikaleks [220]3 years ago
3 0

Answer:

The first one

Explanation:

I can't read them well: it should be 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{5}

** this is the expanded version

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A piece of metal with a mass of 17.1 g was dropped into a graduated cylinder containing 17.00 mL of water. The graduated cylinde
Mademuasel [1]

The density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.

<h3>How to calculate density?</h3>

The density of a substance can be calculated by dividing the mass of the substance by its volume. That is;

Density = mass ÷ volume

According to this question, a piece of metal with a mass of 17.1 g was dropped into a graduated cylinder containing 17.00 mL of water. The density can be calculated as follows:

Density = 17.1g ÷ 17.00mL

Density = 1.005g/mL

Therefore, the density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.

Learn more about density at: brainly.com/question/15164682

#SPJ1

6 0
1 year ago
The half-life of 131I is 8.021 days.What fraction of a sample of 131I remains after 24.063 days
Leno4ka [110]
24.063/8.021 = 3 half lives
(1/2)^3 =1/8 
5 0
3 years ago
A piece of iron is heated to 120'C then placed in a calorimeter containing 50g of water. The water temperature is raised from 30
Lana71 [14]

Answer:

Mass of iron = 59.375 gm

Explanation:

Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C

 The water gains:

     4.18  j/g-C  * 50 * (40-30 C) = 2090 j

The steel gave up 2090 j going from 120 to 40 C

2090 = .44 j/g-C  * m * (120-40)    solve fro m = 59.375 gm

3 0
2 years ago
If 0.400 moles CO and 0.400 moles O2 completely react how many grams of CO2 are produces?
True [87]

If 0.400 moles CO and 0.400 moles O2 completely react, 17.604 grams of CO2 would be produced.

First, let us look at the balanced equation of reaction:

2CO + O_2 ---> 2CO_2

According to the equation, the mole ratio of CO and O2 is 2:1. But in reality, the mole ratio supplied is 1:1. Thus, CO is the limiting reactant while O2 is in excess.

Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.

Recall that: mole = mass/molar mass

Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:

    Mass = mole x molar mass

                 = 0.400 x 44.01

                       = 17.604 grams

More on calculating mass from number of moles can be found here: brainly.com/question/12513822

7 0
2 years ago
2. Using the following data, calculate the average atomic mass of magnesium (give your answer to the nearest
Savatey [412]

Answer: 24.309amu

Explanation:

4 0
3 years ago
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