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dolphi86 [110]
3 years ago
12

PLEASE HELP! Count the total number of atoms in H 2 O: 2 3 4 5 6

Chemistry
2 answers:
Darya [45]3 years ago
8 0
3
two hydrogen and 1 oxygen
lawyer [7]3 years ago
5 0

The total number of atoms is 3.

Make sure to not confuse elements with atoms. Elements are substances used in a chemical equation that cannot be broken down. There are two elements in H2O: hydrogen and oxygen.

Atoms in the compound is the number of elements. Hydrogen would be one atom, but since it has a subscript of 2, it would mean that there are two hydrogen atoms.  Oxygen is another atom, however, it does not have a subscript. Don't make that fool you because there is actually a subscript which is the understood one. That is why there are three atoms.

Hope this helps!!!

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Svet_ta [14]

Answer:

that is all I know sorry hope that may help you :)

Explanation:

Indicator is a substance which shows different colors in acidic and basic medium. Indicators can be natural (derived from natural sources) or artificial ( man-made) for example :

*Litmus is an indicator. Acid turns blue litmus into red while base turns red litmus into blue

* Turmeric solution does not show change in color (remains yellow) in acidic solution and turns red in basic solution.

8 0
2 years ago
What is the correct answer please
Anestetic [448]

Answer:

I think it's the second answer --If you increase the acidity..

I hope answer I can answer your question!

7 0
3 years ago
Base your answer on the information below and your knowledge of chemistry. Methanol can be manufactured by a reaction that is re
Rudiy27

Explanation:

For the given reaction:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

CO(g)+2H_2(g)\rightarrow CH_3OH(g)

Rate=k[CO]^x[H_2]^y

where x and y are order wrt to CO and H_2

According to collision theory , the molecules must collide for a reaction to take place. According to collision theory , the rate of a reaction is proportional to rate of collision of reactants.

Thus with an increase in concentration of reactants , the rate of reaction also increases. This is because if the concentration of reactants increases , the chances of collision between molecules also increases and thus more products wil be formed which in turn increases the rate of reaction.

3 0
3 years ago
8. __H2 + __O2-> __H2O
Rus_ich [418]

Anser:

Explanation:

hope this helps

8 0
2 years ago
An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f
Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

  • Mass of carbon, C:

\frac{32.18}{100}\times 223.94 = 72.06 g

  • Mass of hydrogen, H:

\frac{4.5}{100}\times 223.94 = 10.08 g

  • Mass of chlorine, Cl:

\frac{63.32}{100}\times 223.94 = 141.79 g

Now, the number of each element in the unknown compound is determined by the formula:

number of moles = \frac{given mass}{molar mass}

  • Number of moles of C:

number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole

  • Number of moles of H:

number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole

  • Number of moles of Cl

number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole

Dividing each mole with the smallest number of mole, to determine the empirical formula:

C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}

C_{1.5}H_{2.5}Cl_{1}

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is C_{3}H_{5}Cl_{2}.

Empirical mass = 12\times 3+1\times 5+2\times 35.5 = 112 g/mol

In order to determine the molecular formula:

n = \frac{molar mass}{empirical mass}

n = \frac{223.94}{112} = 1.99 \simeq 2

So, the molecular formula is:

2\times C_{3}H_{5}Cl_{2} =  C_{6}H_{10}Cl_{4}

6 0
3 years ago
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