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4 years ago

12

A toaster transforms electrical energy into _ energy and _ energy. A. heat; light B. heat; kinetic C. heat; potential D.

kinetic; potential

1 answer:

scoray [572]4 years ago

5 0

A. heat; light energies

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Several properties of water are shown. Classify each property as a physical property or a chemical property.

max2010maxim [7]

can be split into hydrogen and oxygen chemical property

is liquid at room temperature physical property

has a density of 1.0 g/cm³ physical property

reacts with certain metals chemical property

Explanation:

The physical properties of matter are the properties that occur when no change is occurring to a matter. They are usually observed with our senses or some simple laboratory experiments.

Some of the physical properties are boiling point, density, state of matter, e.t.c

The chemical properties are the properties that occurs when a matter undergoes some chemical changes.

For example rusting, decomposition, reactivity e.t.c

Learn more:

Chemical properties brainly.com/question/2376134

#learnwithBrainly

8 0

3 years ago

A 100 gram glass container contains 200 grams of water and 50.0 grams of ice all at 0°c. a 200 gram piece of lead at 100°c is ad

ASHA 777 [7]

$0 \; \textdegree{\text{C}}$

Explanation:

Assuming that the final (equilibrium) temperature of the system is above the melting point of ice, such that all ice in the container melts in this process thus

$E(\text{fusion}) = m(\text{ice}) \cdot L_{f}(\text{water}) = 66.74 \; \text{kJ}$ and
$m(\text{water, final}) = m(\text{water, initial}) + m(\text{ice, initial}) = 0.250 \; \text{kg}$

Let the final temperature of the system be $t \; \textdegree{\text{C}}$ . Thus $\Delta T (\text{water}) = \Delta T (\text{beaker}) = t(\text{initial}) - t_{0} = t \; \textdegree{\text{C}}$

$Q(\text{water}) &= &c(\text{water}) \cdot m(\text{water, final}) \cdot \Delta T (\text{water})= 1.047 \cdot t\; \text{kJ}$ (converted to kilojoules)
$Q(\text{container}) &= &c(\text{glass}) \cdot m(\text{container}) \cdot \Delta T (\text{container})= 0.0837 \cdot t \; \text{kJ}$
$Q(\text{lead}) &= &c(\text{lead}) \cdot m(\text{lead}) \cdot \Delta T (\text{lead})= 0.0255 \cdot (100 - t)\; \text{kJ}$

The fact that energy within this system (assuming proper insulation) conserves allows for the construction of an equation about variable $t$ .

$E(\text{absorbed} ) = E(\text{released})$

$E(\text{absorbed} ) = E(\text{fushion}) + Q(\text{water}) + Q(\text{container})$
$E(\text{released}) = Q(\text{lead})$

Confirm the uniformity of units, equate the two expressions and solve for $t$ :

$66.74 + 1.047 \cdot t + 0.0837 \cdot t = 0.0255 \cdot (80 - t)$

$t \approx -55.95\; \textdegree{\text{C}} < 0\; \textdegree{\text{C}}$ which goes against the initial assumption. Implying that the final temperature does <em>not</em> go above the melting point of water- i.e., $t \le 0 \; \textdegree{\text{C}}$ . However, there's no way for the temperature of the system to go below $0 \; \textdegree{\text{C}}$ ; doing so would require the removal of heat from the system which isn't possible under the given circumstance; the ice-water mixture experiences an addition of heat as the hot block of lead was added to the system.

The temperature of the system therefore remains at $0 \; \textdegree{\text{C}}$ ; the only macroscopic change in this process is expected to be observed as a slight variation in the ratio between the mass of liquid water and that of the ice in this system.

3 0

3 years ago

Sound is energy moving in

galben [10]

Whats do you want to know?

7 0

3 years ago

2) Will all atoms behave exactly the same when the temperature is changed?

Butoxors [25]

no...the atoms will not behave the same

as when temperature is increased, the atoms vibration and kinetic energy will also be increased....they come in excited state...

where as when temperature is reduced ,atoms kinetic energy slows down....

7 0

3 years ago

Which is a symbol that represents SI units for temperature.

dsp73

Answer:

A.'C

Explanation:

Please answer my question

5 0

3 years ago

Read 2 more answers