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3 years ago

Factor 140c +28- 14a

Mathematics

2 answers:

saul85 [17]3 years ago

5 0

The answer would be C if you factored out a 14.

ludmilkaskok [199]3 years ago

5 0

Answer:

Step-by-step explanation:

sorry that's all I know for now

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Given the box plot, will the mean or the median provide a better description of the center?

alexandr402 [8]

Answer:

The median, because the data distribution is skewed to the right

Step-by-step explanation:

Min= 10.5

Q1 = 11.5

Median = 12.5

Q3= 13.5

Maximum = 15

The data is skewed towards the right because more values towards the right side as compared to the left side.

For data to be symmetrical, it has same shape on both sides of the median, which in our case is not possible.

So, for skewed data we always prefer median because it is less affected by the outliers and if mean is chosen, the value of mean is biased towards the side that has larger values while median does not get affected by it. So, we choose median.

our correct option will be:

The median, because the data distribution is skewed to the right

6 0

3 years ago

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In the figure at the right DC = 20 cm and AB =36 cm . what is FE? a.16cm b.56cm c.28cm d.46cm

puteri [66]

Answer:

however dc =20 cm is

Step-by-step explanation:

so this isnt contrary to 50

6 0

2 years ago

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Which two decimals are equivalent to 0.6?

ra1l [238]

None of the above

0.6 would be equivalent to 0.60 and 0.600 and 0.600000...but none of the above answers

4 0

4 years ago

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What is the lowest common denominator of:11/5+2/3+1/6

klio [65]

Answer:

5 × 6 = 30

3 ×10 = 30

6 × 5 = 30

4 0

3 years ago

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A physical education teacher plans to divide the seventh graders at Wilson Middle School into teams of equal size of year-ending

Crank

Step-by-step explanation:

Consider the provided information.

The total number of students are: 24+26+21=71

He wants each team will have the same number of students between 5 and 9.

The number between 5 to 9 are 6, 7 and 8.

The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.

Dividing 6 students in each group.

Number of teams: $\frac{71}{6}$ = 11 teams and 5 students.

Dividing 7 students in each group.

Number of teams: $\frac{71}{7}$ = 10 teams and 1 students.

Dividing 8 students in each group.

Number of teams: $\frac{71}{8}$ = 8 teams and 7 students.

Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.

6 0

3 years ago