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zimovet [89]
4 years ago
11

In 1929 Edwin Hubble investigated the claim that distance (explanatory) and radial velocity (response) of extragalactic nebulae

are positively linearly related. Hubble's data is plotted below along with the relevant diagnostic plots. These are the plots and charts needed to analyze data are given below. (Assume all observations are independent) Reference: Hubble, E. (1929) "A Relationship Between Distance and Radial Velocity among Extra-Galactic Nebulae," Proceedings of the National Academy of Science, 168.The explanatory variable is distance (in megaparsecs) and the response is radial velocity (velocity away or towards the earth). Use 3 decimal places for the following questions.(a) What is the regression equation?(b) What is the estimated mean velocity of objects that are 1.9 megaparsecs from Earth?(c) If you were to test the claim that there is a positive linear relationship between the explanatory and response variable, what would your null and alternative hypotheses be?H0: a = 0 and Ha: a < 0H0: a = 0 and Ha: a ? 0 H0: a = 0 and Ha: a > 0H0: b = 0 and Ha: b < 0H0: b = 0 and Ha: b ? 0H0: b = 0 and Ha: b > 0
Mathematics
1 answer:
Serhud [2]4 years ago
5 0

Answer:

honestly this is very confusing could you send a graph?

Step-by-step explanation:

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Desmond is rolling a standard six-sided number cube. He plans to roll it 72 times. About how many times would you expect him to
timama [110]
4 times 18 is 72 use a calculator and divide 72 by each number and you’ll find numbers
7 0
3 years ago
The expression is (10w^3)^2/5w equivalent to
Rasek [7]
The correct answer is:  3)  " <span>20w⁵ </span>" .
__________________________________________
Explanation:
_________________________________________

(10w³)²<span>/ (5w) =

[ 10</span>² * w⁽³*²)<span>  ] /  [5w] =

(100* w</span>⁶) / 5w =

(100/5) * w⁽⁶⁻¹⁾ = 

20 * w⁵ =

20w⁵ ;  which is: Answer choice:  3)  " <span>20w⁵ </span>" .
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3 0
3 years ago
PLSS HELP ILL GIVE POINTS!!!!
Gala2k [10]

Answer:

y=16x+36

Step-by-step explanation:

cleaning services start at $36 for one hour and add $16 to total price per hour.

16(1)+36=52

16(2)+36=68

16(3)+36=84

16(4)+36=100

4 0
3 years ago
At Friday's football game, 1,294 tickets were sold for a total amount of $8,816.00. If each student ticket costs $5.00, and each
NeTakaya

Answer:

512 student tickets.

Step-by-step explanation:

Let x be number of student tickets and y be number of adult tickets.

We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:

x+y=1294...(1)

We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:

5x+8y=8,816...(2)

From equation (1) we will get,

y=1294-x

Substituting this value in equation (2) we will get,

5x+8(1294-x)=8,816

5x+10352-8x=8,816

-3x+10352=8,816

-3x=8,816-10352

-3x=-1536

x=\frac{-1536}{-3}

x=512

Therefore, 512 student tickets were purchased at Fridays football game.

6 0
3 years ago
What’s the answer for number 7????????????
kodGreya [7K]

Choice C, because

\frac{3}{4}  =  \frac{6}{8}

So it's less than what she originally had (which isn't possible)

6 0
3 years ago
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