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zimovet [89]
4 years ago
11

In 1929 Edwin Hubble investigated the claim that distance (explanatory) and radial velocity (response) of extragalactic nebulae

are positively linearly related. Hubble's data is plotted below along with the relevant diagnostic plots. These are the plots and charts needed to analyze data are given below. (Assume all observations are independent) Reference: Hubble, E. (1929) "A Relationship Between Distance and Radial Velocity among Extra-Galactic Nebulae," Proceedings of the National Academy of Science, 168.The explanatory variable is distance (in megaparsecs) and the response is radial velocity (velocity away or towards the earth). Use 3 decimal places for the following questions.(a) What is the regression equation?(b) What is the estimated mean velocity of objects that are 1.9 megaparsecs from Earth?(c) If you were to test the claim that there is a positive linear relationship between the explanatory and response variable, what would your null and alternative hypotheses be?H0: a = 0 and Ha: a < 0H0: a = 0 and Ha: a ? 0 H0: a = 0 and Ha: a > 0H0: b = 0 and Ha: b < 0H0: b = 0 and Ha: b ? 0H0: b = 0 and Ha: b > 0
Mathematics
1 answer:
Serhud [2]4 years ago
5 0

Answer:

honestly this is very confusing could you send a graph?

Step-by-step explanation:

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1 point<br> Solve: 0.75 (x + 200) = 150.5 (2 – 28)<br> type your answer...
adelina 88 [10]

Answer:

\huge \: x =  - 5417.33

Step-by-step explanation:

0.75 (x + 200) = 150.5 (2 – 28) \\

<u>Expand the terms and simplify</u>

That's

0.75x + 150 = 301 - 4214 \\ 0.75x + 150 =  - 3913

Subtract 150 from both sides of the equation

0.75x + 150 - 150 =  - 3913 - 150 \\ 0.75x =  - 4063

<u>Divide both sides by 0.75</u>

\frac{0.75x}{0.75}  =  -  \frac{4063}{0.75}  \\ x =  - 5417.333333

We have the final answer as

<h3>x = - 5417.33 </h3>

Hope this helps you

4 0
3 years ago
Two friends, Ellie and Easton, took summer jobs. The equation y = 19.2x represents Ellie's earnings in dollars and cents, y, for
skad [1K]

Answer:

I don't know what's I don't know I'm really sorry very very very very very very very very very very very very sorry very sorry

4 0
3 years ago
A historian wonders why an ancient civilization disappeared. He suggests that a natural disaster might have destroyed it thousan
Ray Of Light [21]

Answer:

aaaaaaaaaaaaaaa

Step-by-step explanation:

it A

5 0
3 years ago
Read 2 more answers
Plzzzzz Um can someone Please help me I really need help with this
irina [24]

Answer:

<h2>16.26</h2>

Step-by-step explanation:

Pythagorean Theorem | a^2 + b^2 = c^2

1) Plug in a & b

<h2>11^2 + 12^2 = c^2</h2>

2) Rewrite

<h2>c = \sqrt{11^2 + 12^2}</h2>

3) Solve

<h2>c = 16.2788206</h2>

4) Round

<h2>16.26</h2>
4 0
3 years ago
Which models show 40%? Check all that apply. A model with 4 shaded sections and 6 unshaded sections. A model with 40 shaded sect
Amanda [17]

Answer:

A model with 4 shaded sections and 6 unshaded sections.

A model with 40 shaded sections and 60 unshaded sections.

Step-by-step explanation:

Required:

Which models shows 40%

(a) 4 shaded and 6 unshaded

First, we calculate the total sections

Total = 4 + 6

Total = 10

The percentage of the shaded section is:

Shaded = \frac{4}{10} * 100\%

Shaded = 0.4 * 100\%

Shaded = 40\%

(b) 40 shaded and 60 unshaded

First, we calculate the total sections

Total = 40 + 60

Total = 100

The percentage of the shaded section is:

Shaded = \frac{40}{100} * 100\%

Shaded = 0.4 * 100\%

Shaded = 40\%

(c) 2 shaded and 8 unshaded

First, we calculate the total sections

Total = 2 + 8

Total = 10

The percentage of the shaded section is:

Shaded = \frac{2}{10} * 100\%

Shaded = 0.2 * 100\%

Shaded = 20\%

<em>Hence, (a) and (b) shows 40%</em>

8 0
3 years ago
Read 2 more answers
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