Answer:
(a)
(b)
(c)
Step-by-step explanation:
Formula of compound interest:
Compound continuously
A= Amount after t years
P= Principal
r= rate of interest
a)
P=10,000, r=5.5%= 0.055 and t= 5 years, n=2 [ compounded semiannually]
(b)
P=10,000, r=5.5%= 0.055 and t= 5 years, n=12 [ compounded monthly]
(C)
P=10,000, r=5.5%= 0.055 and t= 5 years
Mr. Jackson invested $800 at 6% per year and $ 2400 at 4 % per year
<h3><u>Solution:</u></h3>
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.
Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively
Also, his annual return totaled $144
We can form following equation on the basis of question:-
a = $800
The amount of money invested at 6% = a = 800
The amount of money invested at 4 % = 3a = 3(800) = 2400
So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400
Answer:
Didn't finish sorry. I wish I could help.
Convert the percentage into a decimal:
Set up a proportion using the hours Andrea worked, and the percentage compared to Carmen's workload:
The numerator will represent the hours worked, and the denominator will represent the percentage when compared to Carmen's workload.
Cross multiply the fractions:
Divide both sides by 0.45 to get x by itself:
Carmen worked
20.56 hours last week.