Answer: I think the answer would be (2, -1)
In order to get as many tickets they need 15 business class tickets and 12 economy class tickets (700x15=10,500)(375x12=4500) Which when you add those two makes 15,000.
Answer:
16.....................................
- 6⁹*6ⁿ = 6¹²
- 6⁹⁺ⁿ = ¹²
- 9 + n = 12
- n = 3
17.....................................
- 7⁸/7ⁿ = 7³
- 7⁸⁻ⁿ = 7³
- 8 - n = 3
- n = 5
18.....................................
19.....................................
- 1/10⁵ = 10ⁿ
- 10⁻⁵ = 10ⁿ
- -5 = n
- n = -5
20.....................................
- (8²)ⁿ = 8¹²
- 8²ⁿ = 8¹²
- 2n = 12
- n = 6
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
